Answer:
Rb2CO3(aq)+Fe(C2H3O2)2(aq)--> 2Rb(C2H3O2)(aq) + FeCO3(s)
Explanation:
The reaction shown in the answer is the reaction of rubidium carbonate and iron II acetate. Rubidium is far more reducing than Fe II hence it can displace Fe II from its salt as shown.
The reducing property of metals depends on the value of their individual electrode potential values. For rubidium, its standard reduction potential is -2.98 V while that of Fe II is -0.44V. Hence rubidium can displace Fe II from its salt as shown above.
The answer is 6.022• 10^23 atoms
Answer:
See explanation
Explanation:
The mechanism for the formation of bromohexane from hexene has been clearly shown in the image attached to this answer.
Hexene is attacked by HBr and a carbocation is first formed as shown. The carbocation is flat and planar. it can be attacked on either face by the bromide ion.
Attack on either faces yields a racemic mixture of the R and S enantiomer as shown in the image.
You can use the mechanism shown to fill in the structures.