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3 years ago

Which of these substances are elements?

2 answers:

8 0

An element is a species of atom that has the same amounts of electrons and protons in their nuclei. To know which of these substances are elements, we can look it up in the periodic table of elements. The elements are as follows:

1.silicon
2.lead
3.silicone
5.iodine

Andru [333]3 years ago

8 0

Answer is:

1. silicon.

2. lead.

5. iodine.

Silicon (symbol: Si) is an element with atomic number 14 (14 protons).

Lead (Pb) is an element with atomic number 82.

Iodine (I) is an element with atomic number 53.

Silicone is a compound (polymer) made of silicon, oxygen, hydrogen, carbon and other elements.

Quartz is a compound (mineral) made of silicon and oxygen atoms.

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Answer:

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3 years ago

Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o

alexandr1967 [171]

Answer:

40 grams.

Explanation:

If 20 grams of C is formed from the combination or reaction of A and B chemicals in 10 minutes, 40 grams of C is formed in 20 minutes because the time is doubled so the concentration of C chemical is also doubled. If the time is increased further, more concentration of C chemical is produced until the amount of chemicals A and B are present. If we put an enzyme in the solution, the time of the reaction can be reduced.

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3 years ago

Give the oxidation state of sulfur in (d) H₂S ;

earnstyle [38]

The correct answer is -2 oxidation state.

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5 0

2 years ago

Which cellular process allows a cell to make an exact copy of itself?

Iteru [2.4K]

Explanation:

the answer is letter A. mitosis

6 0

3 years ago

Read 2 more answers

A3B8 + C2 ---> AC2 +

AURORKA [14]

Answer:

A₃B₈ + 5C₂ –> 3AC₂ + 4B₂C

Explanation:

A₃B₈ + C₂ –> AC₂ + B₂C

The equation can be balance as illustrated below:

A₃B₈ + C₂ –> AC₂ + B₂C

There are 3 atoms of A on the left side and 1 atom on the right side. It can be balance by writing 3 before AC₂ as shown below:

A₃B₈ + C₂ –> 3AC₂ + B₂C

There are 8 atoms of B on the left side and 2 atoms on the right side. It can be balance by writing 4 before B₂C as shown below:

A₃B₈ + C₂ –> 3AC₂ + 4B₂C

There are 2 atoms of C on the left side and a total of 10 atoms on the right side. It can be balance by writing 5 before C₂ as shown below:

A₃B₈ + 5C₂ –> 3AC₂ + 4B₂C

Now, the equation is balanced.

5 0

3 years ago