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dezoksy [38]
4 years ago
6

56 out of 128 students went on a trip during vacations what percent of students went on trips

Mathematics
2 answers:
EleoNora [17]4 years ago
8 0
56/128
Simplify
28/64 - 14/32 - 7/16
7/16 = x/100
Cross multiply
700 = 16x
x=43.75
43.75%
Gnoma [55]4 years ago
7 0
The percentage of the students went on a trip during vacation = 56/128 = 43.75 %
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Y = -4x + 3<br> 8x + 2y = 8<br> Solve by using elimination.
ValentinkaMS [17]

Answer:

The equations are not compatible

Step-by-step explanation:

y = -4x + 3

8x + 2y = 8

substitute for y:

8x + 2(-4x + 3) = 8

simplify:

8x - 8x + 6 = 8

6 ≠ 8

3 0
3 years ago
Please solve the table correctly.
Hitman42 [59]

Answer:

See below.

Step-by-step explanation:

No. Triangles       Perimeter

 1                                  14

2                                  18

3                                  22

We see from the table, after the first  perimeter  (= 14),  with  each increase of 1 in the number of triangles,  the perimeter increases by 4.

As an equation it is  P = 14 + 4(n - 1)  where P = perimeter and n = number of triangles.

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3 years ago
Lift pencil (10,7) graph
777dan777 [17]
Ya, what is the question?
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3 years ago
PLEASE ANSWER QUICKLY!!The diameter, D, of a sphere is 10.4 mm. Calculate the sphere's volume, V.
Svetlanka [38]

Answer:

About 588.7 mm^3

Step-by-step explanation:

The formula for the volume of a sphere is (4/3)*pi (or in this case 3.14)*r^3, where r is the radius.

We need the radius. We are given the diameter, 10.4.

The radius is half the diameter, so 10.4/2=5.2.

Use r=5.2 and put it into the formula:

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5 0
3 years ago
Read 2 more answers
I just need no. a please help me to prove this. ​
OleMash [197]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    and         cos A = cos B · cos C

scratchwork:

  A + B + C = π

               A = π - (B + C)

         cos A = cos [π - (B + C)]                              Apply cos

                    = - cos (B + C)                                    Simplify

                    = -(cos B · cos C - sin B · sin C)          Sum Identity

                    = sin B · sin C - cos B · cos C               Simplify

cos B · cos C = sin B · sin C - cos B · cos C               Substitution

2cos B · cos C = sin B · sin C                                        Addition

                     2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}                                     Division

                     2 = tan B · tan C

\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}

<u>Proof LHS → RHS</u>

Given:                              A + B + C = π

Subtraction:                     A = π - (B + C)

Apply tan:                  tan A = tan(π - (B + C))

Simplify:                               = - tan (B + C)

\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)

Substitution:                        = -(tan B + tan C)/(1 - 2)

Simplify:                               = -(tan B + tan C)/-1

                                            = tan B + tan C

LHS = RHS:   tan B + tan C = tan B + tan C  \checkmark

5 0
3 years ago
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