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4 years ago

Nancy rides her horse 26km in 142 minutes. What is her average speed in kilometers per hour?

1 answer:

5 0

10.8 km;You would first need to find out how many km she rides per minute with the equation 26/142. The answer would be .18 km. Now that you know how long it takes her to ride every minute you would need to multiply the number by 60 to find out how many km she rides per hour. 18*60=10.8

You might be interested in

What is precision?what is precision?

RUDIKE [14]

Answer:

According to Oxford Dictionaries "Precision" means "the quality, condition, or fact of being exact and accurate."

Explanation:

Hope this helps! :)

6 0

2 years ago

Read 2 more answers

As you drive away from a radio transmitter, the radio signal you receive from the station is shifted to longer wavelengths.

mylen [45]

Answer:

True

Explanation:

${Apparent}.wavelength = (True.wavelength)(1 +\frac{recession.velocity}{wave.speed})$

As one drive away from the radio station, the recession velocity increases and causes the apparent wavelength to increase accordingly, which in turn causes the True wavelength received from the radio station to increase as well because of their direct relationship as shown in the equation above.

5 0

3 years ago

HELP ME PLEASE

olga55 [171]

1) False

2) True

3) The distance is 17 m

4) The displacement is 2 m south

5) She did not give the direction as either left, or negative.

6) The average speed is 28 mph

7) The average velocity is 12 mph north

8) The average speed is 0.27 m/s

9) False

10) False

Explanation:

Speed is a scalar quantity which tells how fast an object is moving regardless of its direction, and it is calculated as:

$speed=\frac{d}{t}$

where d is the distance covered by the object and t is the time taken. Being a scalar quantity, speed consists only of a value and its units, so no direction needs to be specified.

Velocity is a vector quantity, defined as

$velocity = \frac{d}{t}$

where d is the displacement of the object (a vector connecting the initial position to the final position of motion) and t is the time taken. Being a vector, velocity has both a magnitude and a direction (the same direction as the displacement), so direction here should also be specified.

The distance travelled by the object is just the total length of the path taken, regardless of the direction of each part of the motion.

Here the object moves:

10 meters to the right

7 meters to the left

So, the distance travelled is

d = 10 + 7 = 17 m

The displacement is a vector connecting the initial position to the final position of motion, so we have to compare the starting position with the final position.

Taking x = 0 as initial position, and north as positive direction:

- The object moves 5 m north first (+5)

- The object moves 7 m south (-7)

So, the displacement is

d = +5 + (-7) = -2 m

which means 2 meters south.

As we said previously, displacement is a vector connecting the initial position to the final position of motion. Being a vector, it must have:

- A magnitude (the shortest distance between the initial and final position, in a straight line)

- A direction

Here Jenny reported only the magnitude (3 meters), but not the direction, so she forgot to include the direction of the displacement (which is to the left).

The average speed is given by

$speed=\frac{d}{t}$

where d is the distance and t is the time taken.

The distance is just the total length covered, so:

d = 5 + 2 = 7 miles

The time taken is

t = 1/4 h = 0.25 h

So, the average speed is

$speed=\frac{7}{0.25}=28 mph$

The average velocity is given by

$velocity=\frac{d}{t}$

where d is the displacement and t is the time taken.

The displacement is, taking north as positive direction:

d = +5 + (-2) = 3 miles (north)

The time taken is

t = 1/4 h = 0.25 h

So, the average velocity is

$velocity=\frac{3}{0.25}=12 mph$ (north)

We can calculate the average speed by adding the single measurements and dividing by the number of trials done:

$speed_{avg}=\frac{s_1+s_2+s_3}{3}$

where in this case, N = 3. For this experiment we have:

$s_1 = \frac{0.75 m}{2.5s}=0.30 m/s\\s_2 = \frac{0.75 m}{2.75 s}=0.27 m/s\\s_3=\frac{0.75 m}{2.98 s}=0.25 s$

So the average is

$speed_{avg}=\frac{0.30+0.27+0.25}{3}=0.27 m/s$

Data are said to be:

- Accurate, when the average value of the measurements is close to the actual value

- Precise, when the spread of the measurements done in the different trials is small

Therefore, the first part of the sentence "Data that is accurate, is data that is really close to the actual value" is correct, and the second part "data that is precise is data that is repeated over and over again" is not correct, since we may have several measurements but their spread may be large.

10)

As we said in part 9):

- Accuracy refers to how close the measured value is to the actual value

- Precision refers to the spread (or the uncertainty) on the measured value: the smaller it is, the better the precision

For instance, let's assume that the actual value of a certain variable is 3.0. If we get the following set of data:

2.4, 2.5, 2.4, 2.3

it is precise (the spread is small) but not accurate (since the average, 2.4, is far from the actual value)

while the following set:

3.1, 3.6, 2.4, 3.0

is accurate (the average is around 3.0, so close to the actual value), but not precise (the spread is very large).

Learn more about speed and velocity:

brainly.com/question/8893949