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natulia [17]
2 years ago
14

If you were in a spaceship watching a ball hover at rest (inside the spaceship) in mid-air, and the spaceship suddenly began rap

idly accelerating, what would you see happen to the ball? Why?
Physics
1 answer:
USPshnik [31]2 years ago
4 0

Answer:

It will still hover until the spaceship "hits" or exerts a force on it.

Explanation:

Remember, if there is no net force, there is no acceleration or movement.

In this case, our ball is hovering in the spaceship, and in space, we can assume there is no F_g, and we can assume there is no F_N, nor no forces acting against it.

So, the ball would not move.

However, once the spaceship starts accelerating, the ball would still hover until the spaceship exerts a force on it.

This is because of the same thing as explained above, no forces acting on it, therefore, no acceleration.

Think about it this way.

Imagine you jumped up, then someone threw a ball at you. Now let's imagine you can't move until you hit the floor, meaning that in an ideal situation only  F_g is acting on you. Now again, let's imagine time slows really down for you, but not the ball. Before the ball comes and hits you, you are "hovering" like a ball. But after the ball hits you, you move a little because the ball exerted a force on you.

If you did not understand what I meant above, just forget about it, and think about the fact that if there is a Net force (all the force values added up), then there is acceleration and movement.

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Answer:

  a. 125 kJ

Explanation:

Her total energy is the same as the potential energy she had at the top of the hill:

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How is alternating current generated?
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Compare the momentums of a 50 kg dolphin swimming at 16.4 m/s and a 4100 kg elephant walking 0.20 m/s?
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A projectile is fired with an initial speed of 150 m/s and angle of elevation 60°. (Recall g ≈ 9.8 m/s2. Round your answers to t
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Answer:

1988 m

Explanation:

Range of a projectile

R = U²sin2∅/g...................... Equation 1

Where R = Range, U = Initial velocity, g = acceleration due to gravity, ∅ = Angle of projection.

Given: U = 150 m/s, ∅ = 60°

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