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3 years ago

When balancing a chemical equation, can a coefficient within a chemical equation be adjusted to

2 answers:

8 0

Even though chemical compounds are broken up and new compounds are formed during a chemical reaction, atoms in the reactants do not disappear, nor do new atoms appear to form the products. In chemical reactions, atoms are never created or destroyed. The same atoms that were present in the reactants are present in the products—they are merely reorganized into different arrangements. In a complete chemical equation, the two sides of the equation must be present on the reactant and the product sides of the equation.

Coefficients and Subscripts

There are two types of numbers that appear in chemical equations. There are subscripts, which are part of the chemical formulas of the reactants and products; and there are coefficients that are placed in front of the formulas to indicate how many molecules of that substance is used or produced.

The subscripts are part of the formulas and once the formulas for the reactants and products are determined, the subscripts may not be changed. The coefficients indicate the number of each substance involved in the reaction and may be changed in order to balance the equation. The equation above indicates that one mole of solid copper is reacting with two moles of aqueous silver nitrate to produce one mole of aqueous copper (II) nitrate and two atoms of solid silver.

Hope this help you.

Contact [7]3 years ago

7 0

The answer is down ther

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An unstretched spring has a length of 10. centimeters. When the spring is stretched by a force of 16 newtons, its length is incr

Fed [463]

Answer:

The spring constant of this spring is 200 N/m.

Explanation:

Given:

Original unstretched length of the spring (x₀) = 10 cm =0.10 m [1 cm =0.01 m]

Stretched length of the spring (x₁) = 18 cm = 0.18 cm

Force acting on the spring (F) = 16 N

Spring constant of the spring (k) = ?

First let us find the change in length of the spring or the elongation caused in the spring due to the applied force.

So, Change in length = Final length - Initial length

$\Delta x = x_1-x_0=0.18-0.10=0.08\ m$

Now, restoring force acting on the spring is directly related to its elongation or compression as:

$F=k\Delta x$

Rewriting in terms of 'k', we get:

$k=\dfrac{F}{\Delta x}$

Now, plug in the given values and solve for 'k'. This gives,

$k=\frac{16\ N}{0.08\ m}\\\\k=200\ N/m$

Therefore, the spring constant of this spring is 200 N/m.

5 0

3 years ago

In the diagram, each charge is

Jlenok [28]

Answer:

Quick maths

First you find the fafarick and the lalickc and the caprisum and the joinnt

3 0

3 years ago

An alternating current is set up in an LRC circuit.

Andreyy89

Answer:

(B) Resistor only

Explanation:

Alternating Current: These are currents that changes periodically with time.

An LRC Ac circuit is an AC circuit that contains a Resistor, a capacitor and an inductor, connected in series.

In a purely resistive circuit, current and voltage are in phase.

In a purely capacitive circuit, the current leads the voltage by π/2

In a purely inductive circuit, the current lags the voltage by π/2.

Therefore when a alternating current is set up in LRC circuit, in the resistor, the current and the voltage are in phase.

The right option is (B) Resistor only.

7 0

3 years ago

If you are going 60 mph what is your speed in m per second

LenKa [72]

Answer:

1/60 mps

Explanation:

We would first have to divide 60 by 60 because there is 60mins per hour to get 1mpm. After that we would have to divide 1 by 60 because there are 60 secs in a min. So our final answer after doing 1/60 would be a fraction.

5 0

2 years ago

This questic concerns a tablet that

Vanyuwa [196]

Answer:

The remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

Explanation:

Recall the formula for the decay of a substance at an initial $N_0$ concentration at manufacture:

$N(t)=N_0\,e^{-k\,\,t}$

where k is the decay rate (in our case 0.06/year), and t is the elapsed time in years. Therefore, after 2 years since manufacture we have:

$N=N_0\,e^{-0.06\,\,(2)}\\N=N_0\,e^{-0.12}\\N/N_0=e^{-0.12}\\N/N_0=0.8869$

This in percent form is 88.7 %. That is, the remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

3 0

3 years ago