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antiseptic1488 [7]
3 years ago
9

A fountain is made up of two semicircles and a quarter circle. Find the perimeter of the fountain. Round to the nearest hundredt

h.
PLZ HURRY

Mathematics
1 answer:
Masja [62]3 years ago
4 0

Answer:

75.40 feet

Step-by-step explanation:

For the two small semicircles, the circumference is \frac{1}{2} 2\pi r, or just \pi r. Since the radius is 1/2(16), or 8, the combined circumference of the two semicircles is 16\pi. Now, for the area of the quarter circle in the middle, we see that its radius is 16, and so its circumference is \frac{1}{4} 2\pi r, or \frac{1}{2} \pi 16 = 8\pi. So, the perimeter of the fountain is 16\pi + 8\pi = 24\pi, or about 75.40 feet.

Hope this helped! :)

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Andru [333]
Oh my goodness !  You were doing such an absolutely beautiful job,
as far as you went, but then you ran into some rough road and quit.

You've got the correct expressions for the ages of the three people:

-- Will . . . w
-- Ben . . . w+3
-- Jan . . . 2(w+3)
You slipped up when you expanded Jan's age:  2(w+3) = <u>2w + 6</u> ,
and it was all down hill from there.

Let's do it again, together:

-- Will . . . w
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-- Jan . . . 2w + 6

Total:  (w + w + 2w) + (3 + 6) = 4w + 9

So the equation is:    <em><u>4w + 9 = 41</u></em>
Now you're supposed to solve it.

Subtract 9 from each side:   4w  =  32

Divide each side by 4:        <u>w = 8</u>

-- Will = w . . . . . 8 y.o.
-- Ben = w+3 . . . 11 y.o.
-- Jan = 2(w+3) . . 22 y.o.

When will Jan be twice as old as Will ?
That'll happen in 'x' years.
At that time, Will will be (8+x) and Jan will be (22+x),
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22 + x  =  2(8 + x)

22 + x  =  16 + 2x

Subtract 'x' from each side:    22  =  16 + x

Subtract  16  from each side:  <em>  6 = x</em>

<u>Check:</u>

In 6 years, Jan will be (22+6) = 28,
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28 = twice as old as 14.      yay!

Can I make a little suggestion ?
I'm going to make it anyway:

Your problem was neatness.
You were doing great work in that big open space on the sheet, but it
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