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3 years ago

Explain why 2n+1 must be an odd number

1 answer:

4 0

If is an integer (a whole number), then the expression represents an even number, because even numbers are the multiples of 2. The expressions 2 n − 1 and 2 n + 1 can represent odd numbers, as an odd number is one less, or one more than an even number.

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500.000.000 written in scientific notation?

Natali [406]

$\large \mathfrak{Answer : }$

Scientific notation for above vLue is :

$5 \times 10 {}^{8}$

8 0

3 years ago

PLEASE HELP 12 POINTS

Ahat [919]

To find the answer, you have to find 22% of the total amount of money in the budget. The budget is 12,500,000, so 22% of that would be 12,500,000*22/100=12,500,000*.22=2,750,000

$2,750,000 is dedicated to research.

3 0

4 years ago

Read 2 more answers

Evaluate the limits<br><br>

julsineya [31]

$x > \ln(x)$ for all $x$ , so

$\displaystyle \lim_{x\to\infty} (\ln(x) - x) = - \lim_{x\to\infty} x = \boxed{-\infty}$

Similarly, $\displaystyle \lim_{x\to\infty} (x-e^x) = - \lim_{x\to\infty} e^x = \boxed{-\infty}$

We can of course see the limits are identical by replacing $x\mapsto e^x$ , so that

$\displaystyle \lim_{x\to\infty} (\ln(x) - x) = \lim_{x\to\infty} (\ln(e^x) - e^x) = \lim_{x\to\infty} (x - e^x)$

You can also rewrite the limands to accommodate the application of l'Hôpital's rule. For instance,

$\displaystyle \lim_{x\to\infty} (x - e^x) = \ln\left(\exp\left(\lim_{x\to\infty} (x - e^x)\right)\right) = \ln\left(\lim_{x\to\infty} e^{x-e^x}\right) = \ln\left(\lim_{x\to\infty} \frac{e^x}{e^{e^x}}\right)$

Using the rule, the limit here is

$\displaystyle \lim_{x\to\infty} \frac{(e^x)'}{\left(e^{e^x}\right)'} = \lim_{x\to\infty} \frac{e^x}{e^x e^{e^x}} = \lim_{x\to\infty} \frac1{e^{e^x}} = 0$

so the overall limit is

$\displaystyle \lim_{x\to\infty} (x - e^x) = \ln\left(\lim_{x\to\infty} \frac{e^x}{e^{e^x}}\right) = \ln(0) = \lim_{x\to0^+} \ln(x) = -\infty$

6 0

2 years ago

What is the volume of the triangular prism below 7.8 in 6 in 5 in 11.5 in

Zarrin [17]

Answer:

D. 172.5 inches cubed

Step-by-step explanation:

Have a good day :)

8 0

3 years ago

Given the function f(x) = 5x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

nadezda [96]

Average rate of change from x = 0 to x = 1 is $\frac{f(1)-f(0)}{1-0}= \frac{5(1)-5(0)}{1}=5$
Average rate of change from x = 2 to x = 3 is $\frac{f(3)-f(2)}{3-2}= \frac{5(3)-5(2)}{1}=15-10=5$
The average rate of change of both sections are equal.

4 0

3 years ago