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3 years ago

Cos(2pi/28)cosec(3pi/28)+cos(6pi/28)cosec(9pi/28)+cos(18pi/28)cosec(27pi/28)=0

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

7 0

Sorry, I cannot answer this as this is a question I don't understand. You are pretty High-Tech BTW.

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2 years ago

Solve for x.<br> 3(3x + 3) - 5x – 4= 25

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Answer:

x = 5

Step-by-step explanation:

$3(3x + 3) - 5x - 4= 25\\\\9x+9-5x-4=25\\\\9x-5x+9-4=25\\\\4x+5=25\\\\4x+5-5=25-5\\\\4x=20\\\\\frac{4x=20}{4}\\\\\boxed{x=5}$

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3 years ago

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3 years ago

4(3n-2)^(-3/2)+1=347/343

blagie [28]

Greetings and Happy Holidays!

Solve for n.
$4(3n-2)^{\frac{-3}{2}}+1= \frac{347}{343}$

Add -1 to both sides.
$(4(3n-2)^{\frac{-3}{2}}+1)+(-1)=(\frac{347}{343})+(-1)$

$4(3n-2)^{\frac{-3}{2}}=\frac{347}{343}-1$

$4(3n-2)^{\frac{-3}{2}}=\frac{347}{343}-\frac{343}{343}$

$4(3n-2)^{\frac{-3}{2}}=\frac{4}{343}$

Divide both sides by 4
$\frac{4(3n-2)^{\frac{-3}{2}}}{4}=\frac{\frac{4}{343}}{4}$

$\frac{4(3n-2)^{\frac{-3}{2}}}{4}=\frac{4}{343}(\frac{1}{4})$

$\frac{4(3n-2)^{\frac{-3}{2}}}{4}=\frac{4}{1372}$

$\frac{4(3n-2)^{\frac{-3}{2}}}{4}=\frac{1}{343}$

$(3n-2)^{\frac{-3}{2}}=\frac{1}{343}$

Solve the Exponent.
$((3n-2)^{\frac{-3}{2}})^{\frac{2}{-3}} =\frac{1}{343}^{\frac{2}{-3}}$

$3n-2=49$

Add 2 to both sides.
$(3n-2)+2=(49)+2$

$3n=51$

Divide both sides by 3.
$\frac{3n}{3}= \frac{51}{3}$

$n=17$

The Answer Is:
$\left[\begin{array}{ccc}n=17\end{array}\right]$

Hope this helped!
-Benjamin

5 0

3 years ago