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3 years ago

7

Static charges can be applied to neutral objects by friction, induction or conduction. What do all of these methods utilize to c

reate this charge?
a.protons
b.electrons
c.heat energy

1 answer:

MatroZZZ [7]3 years ago

5 0

Electrons are valence and free moving so they take place in charge transfer

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If kb for nx3 is 4.0×10−6, what is the poh of a 0.175 m aqueous solution of nx3?

Elena-2011 [213]

<h3><u>Answer;</u></h3>

pOH = 3.08

<h3><u>Explanation;</u></h3>

NX3 + H2O <----> NHX3+ + OH-

Kb = 4.0 x 10^-6

Kb = c(NH₄⁺) · c(OH⁻) ÷ c(NH₃).

c(NH₄⁺) = c(OH⁻) = x.

x² = Kb · c(NH₃)

x² = 4.0 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.

x = c(OH⁻) = √(7.0 × 10⁻⁷)

= 8.367 × 10⁻⁴

pOH = -log(c(OH⁻))

=- log ( 8.367 × 10⁻⁴)

<u>= 3.08</u>

7 0

3 years ago

What is the molarity of 500 ml of a solution containing 85.0g AgNO3? A) 0.5 M B) 1.0 M C) 2.0 M D) 5.0 M

kari74 [83]

Consider the equation for calculating molarity: (no. of mole of solute)÷(volume of solution)

First, let's find the no. of mole of solute in AgNO3. As (no. of mole) = mass / molar mass

no. of mole of 85.0g of AgNO3 = 85.0/(107.9+14.0+16.0x3)

=0.5mol

Since the volume of the solution has to be in dm3, just divide the volume in cm3 by 1000 to get the volume in dm3.

Volume of solution = 500/1000

= 0.5 dm3

Therefore, the molarity is

0.5/0.5

=1.0M

The answer should be B.

3 0

3 years ago

The following Lewis diagram represents the valence electron configuration of a main-group element. This element is in group 2A A

Paraphin [41]

<u>Answer:</u> The symbol of the ion formed is $Ca^{2+}$

<u>Explanation:</u>

An ion is formed when a neutral atom looses or gains electrons.

When an atom looses electrons, it results in the formation of positive ion known as cation.
When an atom gains electrons, it results in the formation of negative ion known as anion.

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom is determined by the atomic number of that atom.

The element present in Group 2-A and in period 4 is Calcium (Ca)

Electronic configuration of Ca atom: $1s^22s^22p^63s^23p^64s^2$

This atom will loose 2 electrons to attain stable electronic configuration similar to Argon element (noble gas)

The electronic configration of $Ca^{2+}\text{ ion}=1s^22s^22p^63s^23p^6$

Hence, the symbol of the ion formed is $Ca^{2+}$

4 0

3 years ago

A car travelling at 50m/s produces a force of 200N. What is the power of the engine in kilowatts(KW).

Zina [86]

Answer:

10 kilowatts or 10,000 kw

Explanation:

Power = Force × Velocity

Given that:

Velocity of car is 50 m/s

The force is 200N

The power would be:

P = 200 × 50

P = 10,000 W

Notice that it only reaches watts because of the unit of the velocity is m/s. Standard unit to make Kw is km.

Since:

1 kw = 1000 w

10 kw = 10000 w

Credits to the person below me for correction.

6 0

3 years ago

Read 2 more answers

1. Using the balanced equation, answer the following questions:

nalin [4]

Answer:

a) 2.53 × 10²³ molecules of O₂

b) 31.90 g of KCl

Explanation:

The balance chemical equation for given decomposition reaction is as follow;

2 KClO₃ → 2 KCl + 3 O₂

<h3>Part 1:</h3>

Step 1: <u>Calculate Moles for given amount of KClO₃;</u>

Moles = Mass / M.Mass

Moles = 34.35 g / 122.55 g/mol

Moles = 0.280 moles of KClO₃

Step 2: <u>Find out moles of O₂ produced;</u>

According to eq,

2 moles of KClO₃ produces = 3 moles of O₂

So,

0.280 moles of KClO₃ will produce = X moles of O₂

Solving for X,

X = 0.280 mol × 3 mol / 2 mol

X = 0.42 moles of O₂

Step 3: <u>Calculate No. of Molecules of O₂ as,</u>

No. of Molecules = Moles × 6.022 × 10²³

No. of Molecules = 0.42 mol × 6.022 × 10²³ molecules/mol

No. of Molecules = 2.53 × 10²³ molecules of O₂

<h3>Part 2:</h3>

Step 1: <u>Calculate Moles for given amount of KClO₃;</u>

Moles = Mass / M.Mass

Moles = 52.53 g / 122.55 g/mol

Moles = 0.428 moles of KClO₃

Step 2: <u>Find out moles of KCl produced;</u>

According to eq,

2 moles of KClO₃ produces = 2 moles of KCl

So,

0.428 moles of KClO₃ will produce = X moles of KCl

Solving for X,

X = 0.428 mol × 2 mol / 2 mol

X = 0.428 moles of KCl

Step 3: <u>Calculate Mass of KCl as;</u>

Mass = Moles × M.Mass

Mass = 0.428 mol × 74.55 g/mol

Mass = 31.90 g of KCl

6 0

3 years ago