1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
madreJ [45]
3 years ago
12

If kb for nx3 is 4.0×10−6, what is the poh of a 0.175 m aqueous solution of nx3?

Chemistry
1 answer:
Elena-2011 [213]3 years ago
7 0
<h3><u>Answer;</u></h3>

pOH = 3.08

<h3><u>Explanation;</u></h3>

NX3 + H2O <----> NHX3+ + OH-  

Kb = 4.0 x 10^-6

Kb = c(NH₄⁺) · c(OH⁻) ÷ c(NH₃).

c(NH₄⁺) = c(OH⁻) = x.

x² = Kb · c(NH₃)

x² = 4.0 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.

x = c(OH⁻) = √(7.0 × 10⁻⁷)

    = 8.367 × 10⁻⁴

pOH = -log(c(OH⁻))

        =- log ( 8.367 × 10⁻⁴)

        <u>= 3.08</u>

You might be interested in
Draw the structure of the neutral product formed in the reaction of dimethyl malonate and methyl vinyl ketone.
Dmitriy789 [7]

Answer:

Explanation:

The reaction between dimethyl malonate which is an active methylene group with an (∝, β-unsaturated carbonyl compound) i.e methyl vinyl ketone is known as a Micheal Addition reaction. The reaction mechanism starts with the base attack on the β-carbon to remove the acidic ∝-hydrogens and form a carbanion. The carbanion formed(enolate ion) attacks the methyl vinyl ketone(i.e. a nucleophilic attack at the β-carbon) to give a Micheal addition product, this is followed by the protonation to give the neutral product.

3 0
2 years ago
When the compound BaCl2 forms , what happens to the Ba and Cl ions
Korvikt [17]
Ba stays as Ba+2 and Cl stays as Cl-
6 0
2 years ago
Read 2 more answers
Do ghosts exists ?? ...​
Nesterboy [21]

Answer:

no

Explanation:

it is human imagination about scary things that brought about ghost

5 0
2 years ago
If the dehydration reaction of an alcohol is successful. What changes would be seen in the ir spectrum for the product compared
Bess [88]

If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,

  • The O-H and  C-O  band is disappear from stating material
  • The addition of a C-C double bond band in the product.

In dehydration reaction of alcohol (  O-H and  C-O bond ) contain , the water molecule ( H_{2}O ) is release from the reactant and C-C double bond is form which is known as alkene in the product .

The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of  dehydration reaction of an alcohol. It means  O-H band is disappear from stating material.

learn about IR SPECTRUM

brainly.com/question/15452269

#SPJ4

4 0
1 year ago
Given the following data on a 6 foot tall, 210 pound male, perform the appropriate calculations and evaluate the values related
sladkih [1.3K]
A correct B incorrect C incorrect E correct
3 0
2 years ago
Other questions:
  • What did Stephen hawking do that was important
    10·1 answer
  • Describe the quantum model of an atom in terms of energy levels, sublevels, and orbitals. (Any atom is acceptable)
    8·1 answer
  • True or False: Anushka set out to create something to measure
    15·2 answers
  • 1.75 M hydrochloric acid is used in a titration with 47.8ml of sodium hydroxide, at the equivalence points 29.3ml of acid was ad
    5·1 answer
  • How many moles of gas does it take to occupy 120 L at a pressure of 233 kPa and a temperature of 340 K?
    8·2 answers
  • What could you do to make yeast dough rise more slowly?
    9·2 answers
  • What are the complete Ionic and Net Ionic equations for the following
    14·1 answer
  • What is the result of wave motion on water particles?
    7·2 answers
  • PLEASE HELP i’ll mark brainliest ( reporting fake answers)
    13·1 answer
  • 1.- Ilumina de amarillo los verbos en pretérito y de verde los verbos en copretérito.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!