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madreJ [45]
3 years ago
12

If kb for nx3 is 4.0×10−6, what is the poh of a 0.175 m aqueous solution of nx3?

Chemistry
1 answer:
Elena-2011 [213]3 years ago
7 0
<h3><u>Answer;</u></h3>

pOH = 3.08

<h3><u>Explanation;</u></h3>

NX3 + H2O <----> NHX3+ + OH-  

Kb = 4.0 x 10^-6

Kb = c(NH₄⁺) · c(OH⁻) ÷ c(NH₃).

c(NH₄⁺) = c(OH⁻) = x.

x² = Kb · c(NH₃)

x² = 4.0 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.

x = c(OH⁻) = √(7.0 × 10⁻⁷)

    = 8.367 × 10⁻⁴

pOH = -log(c(OH⁻))

        =- log ( 8.367 × 10⁻⁴)

        <u>= 3.08</u>

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You are given a cube of lead that is 1.000 cm on each side. The density of lead is 11.35. How many atoms of lead are in the samp
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<u>11.35 g</u><u> </u><u>atoms </u><u>of lead are in the sample.</u>

What does density mean?

  • The density of an area refers to the quantity of things—which may include people, animals, plants, or objects—there are in it.
  • Divide the number of objects by the area's measurement to determine density.
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We can calculate the volume of the cube by cubing the side of the cube.

Volume of cube = ( 1.000 cm)³

                           = 1.000 cm³

We can now determine the amount of lead in the cube by multiplying by the density. Because we know we have a 1.000 cubic centimeter and that lead has a density of 11.35 grams per cubic centimeter, we have 11.35 grams of lead.

           =  ( 1.000 cm³) ( 11.35 \frac{g}{cm^{3} } )

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Here Copper is at a temperature of 60 degree Celsius and aluminum is at 40 degree Celsius. Thus, heat will flow from Cu to Al.

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The heat liberated can be expressed as follows:

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