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irinina [24]
3 years ago
8

What is the boiling point of kerosene

Chemistry
1 answer:
dexar [7]3 years ago
6 0

Answer: The boiling point of kerosene ranges from around 150 to 300 degrees Celsius normally being closer to 300 degrees Celsius.

Explanation:

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What does an increase of 1 pH number represent?
Gennadij [26K]

Answer: B

Explanation:

5 0
3 years ago
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What volume of argon gas is equal to 1.60 grams of argon
Novosadov [1.4K]

Answer:

0.908 L.

Explanation:

  • Firstly, we should calculate the number of moles of 1.60 g argon.
  • n of Ar = mass / molar mass of Ar = (1.60 g) / (39.948 g/mol) = 0.04 mol.
  • |t is established  and known that the molar volume of a gas at STP (Standard Temperature and Pressure) is equal to 22.4 L for 1 mole of any ideal gas at a temperature of 273.15 K and a pressure of 1.00 atm.

<u><em>using cross multiplication:</em></u>

1.0 mole of Ar gas will occupy → 22.7 L

0.04 mole of Ar gas will occupy → ??? L

∴ The volume  occupied by Ar = (0.04 mole) (22.7 L) / (1.0 mole) = 0.908 L.


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3 years ago
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Which of the following states that submicroscopic particles of all matter are in constant random motion?
Gwar [14]
The best and most correct answer among the choices provided by the question is the third choice. A theory stating <span>particles of all matter are in constant random motion would be the kinetic theory. I </span><span>hope my answer has come to your help. God bless and have a nice day ahead!</span>
4 0
3 years ago
A 30-0 g sample of water at 280 K is mixed with 50.0 g of water at 330 K. How would you calculate the final temperature of the m
aliya0001 [1]

Answer:

311.25k

Explanation:

The question assumes heat is not lost to the surroundings, therefore

heat emitted from hotter sample ( q_{\ lost} )= heat absorbed by the less hotter  sample( q_{\ gain} )

The relationship between heat (q), mass (m) and temperature (t) is q = mc\Delta t

where c is specific heat capacity, \Delta t temperature change.

\Delta t = t_{\ final} - t_{\ initial}

equating both heat emitted and absorb

-q_{\ lost} = q_{\ gain}

-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})

where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.

C will cancel out since both are water and they have the same specific heat capacity.

so we have

-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})

where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?

-50 * (t_{final} - 330) = 30 *  (t_{final} - 280)

-50t_{final} + 16500 = 30t_{final} - 8400

80t_{final} = 16500+8400

80t_{final} = 24900

t_{final} = 24900/80 = 311.25k

8 0
3 years ago
What is the general formula for a straight-chain alkane?
TEA [102]

Answer:

The general formula for a straight chain alkane is CnH(2n+...so correct option is C and D

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