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3 years ago

What is the boiling point of kerosene

1 answer:

6 0

Answer: The boiling point of kerosene ranges from around 150 to 300 degrees Celsius normally being closer to 300 degrees Celsius.

Explanation:

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Calculate the concentration of all species in a 0.160 m solution of h2co3.

enot [183]

H₂CO₃ ⇔ HCO₃⁻ + H⁺

I 0.160 0 0

C -x +x +x

E 0.160-x +x +x

Ka1 = [HCO₃⁻][H⁺] / [H₂CO₃]

4.3 x 10⁻⁷ = x² / (0.160-x) (x is neglected in 0.160-x = 0.160)

x² = 6.88 x 10⁻⁸

x = 2.62 x 10⁻⁴

HCO₃⁻ ⇔ CO₃⁻² + H⁺

I 2.62 x 10⁻⁴ 0 2.62 x 10⁻⁴

C -x +x +x

E 2.62 x 10⁻⁴ - x +x 2.62 x 10⁻⁴ + x

Ka2 = [CO₃⁻²][H⁺] / [HCO₃⁻]

5.6 x 10⁻¹¹ = x(2.62 x 10⁻⁴ + x) / (2.62 x 10⁻⁴ - x)

x = 5.6 x 10⁻¹¹

Thus,

[H₂CO₃] = 0.160 - (2.62 x 10⁻⁴) = 0.16 M

[HCO₃⁻] = 2.62 x 10⁻⁴ - ( 5.6 x 10⁻¹¹) = 2.6 x 10⁻⁴ M

[CO₃⁻²] = 5.6 x 10⁻¹¹ M

[H₃O⁺] = 2.62 x 10⁻⁴ + 5.6 x 10⁻¹¹ = 2.6 x 10⁻⁴ M

[OH⁻] = 3.8 x 10⁻¹¹

8 0

3 years ago

Which type of scientist would observe the spread of a species of red fire ants

diamong [38]

It would be a biologist

7 0

3 years ago

Noble gas compounds like KrF, XeCl, and XeBr are used in excimer lasers. Draw an approximate molecular orbital diagram appropria

Aneli [31]

Answer:

Here's what I get.

Explanation:

The MO diagrams of KrBr, XeCl, and XeBr are shown below.

They are similar, except for the numbering of the valence shell orbitals.

Also, I have drawn the s and p orbitals at the same energy levels for both atoms in the compounds. That is obviously not the case.

However, the MO diagrams are approximately correct.

The ground state electron configuration of KrF is

$(1\sigma_{g})^{2}\, (1\sigma_{u}^{*})^{2} \, (2\sigma_{g})^{2} \, (2\sigma_{u}^{*})^{2} \, (3\sigma_{g})^{2} \, (1\pi_{u})^{4} \, (1\pi_{g}^{*})^{4} \, (3\sigma_{g}^{*})^{1}$

KrF⁺ will have one less electron than KrF.

You remove the antibonding electron from the highest energy orbital, so the bond order increases.

The KrF bond will be stronger.

6 0

3 years ago

Arrange the molecules H2O, NH3, Ar, NaCl in order of expected increasing boiling points. 1. None of these 2. NaCl, H2O, NH3, Ar

Aleks04 [339]

Answer:

Option (4) is correct

Explanation:

NaCl is an ionic solid. $Na^{+}$ and $Cl^{-}$ ions are held together by strong coloumbic attractive force. Hence NaCl has highest boiling point'
Ar is a monoatomic molecule. Hence only weak london dispersion force exists between Ar atom/molecules. Hence it requires lowest amount of energy to boil and thereby possess lowest boiling point.
$NH_{3}$ and $H_{2}O$ are polar protic molecules. Hence they possess london dispersion force, dipole-dipole force and hydrogen bonding as intermolecular forces.
Dipole-dipole force is stronger in $H_{2}O$ than $NH_{3}$ due to more polar O-H bond than N-H bond. Also molecular weight of $H_{2}O$ is higher than $NH_{3}$ . So, more energy is required to boil $H_{2}O$ . So, $H_{2}O$ has higher boiling point than $NH_{3}$