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Paha777 [63]
3 years ago
13

A car travelling at 50m/s produces a force of 200N. What is the power of the engine in kilowatts(KW).

Chemistry
2 answers:
Zina [86]3 years ago
6 0

Answer:

10 kilowatts or 10,000 kw

Explanation:

Power = Force × Velocity

Given that:

Velocity of car is 50 m/s

The force is 200N

The power would be:

P = 200 × 50

P = 10,000 W

Notice that it only reaches watts because of the unit of the velocity is m/s. Standard unit to make Kw is km.

Since:

1 kw = 1000 w

10 kw = 10000 w

Credits to the person below me for correction.

zheka24 [161]3 years ago
5 0

Answer:

10 KW

Explanation:

The speed of the car is 50m/s.

The force of 200N is produced.

Power (W) = Velocity (m/s) × Force (N)

Power (W) = 50 × 200

Power (W) = 10000

1 Nm/s = 1 Watt

The power in Watts is 10000. The question asks for the power in kilowatts.

1 kilowatts = 1000 Watts

10000/1000 = 10 kilowatts

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A nucleus collides with a neutron and splits, releasing energy.

Explanation:

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2 years ago
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How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?
tino4ka555 [31]

Taking into account the reaction stoichiometry, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CO₂ + 4 H₄  → CH₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CO₂: 1 mole
  • H₄: 4 moles  
  • CH₄: 1 mole
  • H₂O: 2 moles

<h3>Moles of CH₄ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?

moles of CH_{4} =\frac{85.1 moles of CO_{2}x4 moles of CH_{4} }{1 moles of CO_{2}}

<u><em>moles of CH₄= 340.4 moles</em></u>

Then, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

6 0
1 year ago
A legal right to use the property owned by someone else in a specified manner is known as an?
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I believe as sharing bit

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En un recipiente cerrado y rígido se introdujo una mezcla gaseosa a cierta temperatura y las presiones parciales de cada gas son
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Answer:

Qp > Kp, por lo tanto, la presión parcial de BrF₃(g) aumenta hasta alcanzar el equilibrio.

Explanation:

Paso 1: Escribir la ecuación balanceada

BrF₃ (g) ⇌ BrF(g) + F₂(g)      Kp(T) = 64,0

Paso 2: Calcular el cociente de reacción (Qp)

Qp = pBrF × pF₂ / pBrF₃

Qp = 1,50 × 2,00 / 0,0150 = 200

Paso 3: Sacar una conclusión

Dado que Qp > Kp, la reacción se desplazará hacia la izquierda para alcanzar el equilibrio, es decir, la presión parcial de BrF₃(g) aumenta hasta alcanzar el equilibrio.

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3 years ago
Increasing temperature makes a
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High temperature increases the number of high energy collisions

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Increasing the temperature a reaction takes place at increases the rate of reaction. At higher temperatures, particles can collide more often and with more energy, which makes the reaction take place more quickly.

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