Question

A magnetic B field of strength 18 T is perpendicular to a conducting loop of wire measuring 0.9 square meters with 30 turns. If the B field is linearly reduced to zero in 4 s, then what is the magnitude of the induced emf voltage? (in units of V).

Answer 1

Answer:

magnitude of the induced emf voltage = 121.5 V

Explanation:

given data

magnetic field of strength B =  18 T

area = 0.9 m²

no of turn = 30 turns

Δt = 4s

to find out

magnitude of the induced emf voltage

solution

we get her magnitude of the induced emf voltage that is express as

magnitude of the induced emf voltage = $\frac{d\phi}{dt}$   ......1

magnitude of the induced emf voltage = $n*a * \frac{dB}{dt}$

magnitude of the induced emf voltage = $30* 30* \frac{18}{4}$

magnitude of the induced emf voltage = 121.5 V