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Eva8 [605]
3 years ago
10

How is the acceleration of an object in newtons second law related to its mass and the net force on it?

Physics
2 answers:
ki77a [65]3 years ago
8 0

Answer:

C) Acceleration is directly proportional to net force divided by mass.

Explanation:

As per Newton's 2nd law we know that net force on the object is product of mass and acceleration of the object

so we will have

F = ma

so here we can say that the force and mass of the object is directly depends on each other and the equation is just product of mass and acceleration.

So in order to find the acceleration we have

a = \frac{F}{m}

so we will have

C) Acceleration is directly proportional to net force divided by mass.

9966 [12]3 years ago
4 0
B) Acceleration is directly proportional to the mass of the object
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If you increase the elasticity of a material, what happens to the speed of a mechanical wave going through it?
Sophie [7]

Answer:

At the molecular level, materials are held together by bonds, which act like springs for small displacements from the equilibrium spacing between neighboring atoms. Push the atoms close, the bond pushes back to keep them apart. Pull them apart, the bond pulls the atoms closer. For those small displacements, it acts like a spring

The speed of the wave will be related to the stiffness of of those springs - you compress the material - how quickly do all of those little springs rebound and push their neighboring atoms away, sending that wave of compression through the material.

Explanation:

5 0
2 years ago
A 0.5 kg basketball moving 5 m/s to the right collides with a 0.05 kg tennis
Natali5045456 [20]

Answer:

A. 1.4 m/s to the left

Explanation:

To solve this problem we must use the principle of conservation of momentum. Let's define the velocity signs according to the direction, if the velocity is to the right, a positive sign will be introduced into the equation, if the velocity is to the left, a negative sign will be introduced into the equation. Two moments will be analyzed in this equation. The moment before the collision and the moment after the collision. The moment before the collision is taken to the left of the equation and the moment after the collision to the right, so we have:

M_{before} = M_{after}

where:

M = momentum [kg*m/s]

M = m*v

where:

m = mass [kg]

v = velocity [m/s]

(m_{1} *v_{1} )-(m_{2} *v_{2})=(m_{1} *v_{3} )+(m_{2} *v_{4})

where:

m1 = mass of the basketball = 0.5 [kg]

v1 = velocity of the basketball before the collision = 5 [m/s]

m2 = mass of the tennis ball = 0.05 [kg]

v2 = velocity of the tennis ball before the collision = - 30 [m/s]

v3 =  velocity of the basketball after the collision [m/s]

v4 = velocity of the tennis ball after the collision = 34 [m/s]

Now replacing and solving:

(0.5*5) - (0.05*30) = (0.5*v3) + (0.05*34)

1 - (0.05*34) = 0.5*v3

- 0.7 = 0.5*v

v = - 1.4 [m/s]

The negative sign means that the movement is towards left

3 0
2 years ago
Which of the following describes a role of gravity in the formation of our solar system?
Black_prince [1.1K]
I think the answer is A because it is gravity that caused the planets to form and start orbiting around the nearest star which is the sun
5 0
3 years ago
Read 2 more answers
Whats 6 3/7 ×1 5/9.
aniked [119]
6 3/7 * 1 5/9
45/7 * 14/9
630/63
10
7 0
3 years ago
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An experimenter finds that standing waves on a string fixed at both ends occur at 24 Hz and 32 Hz , but at no frequencies in bet
Vera_Pavlovna [14]

Answer:

8 Hz

Explanation:

Given that

Standing wave at one end is 24 Hz

Standing wave at the other end is 32 Hz.

Then the frequency of the standing wave mode of a string having a length, l, is usually given as

f(m) = m(v/2L), where in this case, m could be 1. 2. 3. 4 etc

Also, another formula is given as

f(m) = m.f(1), where f(1) is the fundamental frequency..

Thus, we could say that

f(m+1) - f(m) = (m + 1).f(1) - m.f(1) = f(1)

And as such,

f(1) = 32 - 24

f(1) = 8 Hz

Then, the fundamental frequency needed is 8 Hz

4 0
3 years ago
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