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olga2289 [7]
3 years ago
15

A single loop of area 0.193 m2 is placed perpendicular to a magnetic field of 0.374 T. The loop is rotated about an axis lying i

n the plane of the loop and passing through its center. An instantaneous emf of 9.21 Volts is generated when the plane of the loop makes an angle of 45 o with the field direction. What is the angular speed of the loop (rad/s)
Physics
1 answer:
DENIUS [597]3 years ago
4 0

Answer: The angular speed w of the loop = 181 rad/s

Explanation:

Given that;

Area A = 0.193 m2 

Magnetic field B = 0.374 T

E.m.f = 9.24v

Ø = 45 degree

According to Faraday's law when the magnetic flux linking a circuit changes, an electromotive force is induced in the circuit proportional to the rate of change of the flux linkage.

Using the formula

E.m.f = NABwcosØ

Where w = angular velocity.

Let assume that N = 1 then,

9.24 = 0.193 × 0.374 × w × cos45

9.24 = 0.051w

w = 9.24/0.051

w = 181 m/s

Therefore, the angular speed w of the loop = 181 rad/s

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