A single loop of area 0.193 m2 is placed perpendicular to a magnetic field of 0.374 T. The loop is rotated about an axis lying i
1 answer:
You might be interested in
Answer:
Radius between electron and proton
Explanation:
The motion of the electron is carried out in the orbit due to the balancing of the electrostatic force between the proton and the electron and the centripetal force acting on the electron.
The electrostatic force is given as =
Where,
k = coulomb's law constant (9×10⁹ N-m²/C²)
q₁ and q₂ = charges = 1.6 × 10⁻¹⁹ C
r = radius between the proton and the electron
Also,
Centripetal force on the moving electron is given as:
=
where,
= mass of the electron (9.1 ×10⁻³¹ kg)
V = velocity of the moving electron (given: 6.1 ×10⁵ m/s)
Now equating both the formulas, we have
=
⇒
substituting the values in the above equation we get,
⇒
The minimum frequency is
while the maximum frequency is
Using the relationship between frequency f of a wave, wavelength
and the speed of the wave v, we can find what wavelength these frequencies correspond to:
So, the wavelengths of the radio waves of the problem are within the range 188-545 m.
while the maximum frequency is
Using the relationship between frequency f of a wave, wavelength
So, the wavelengths of the radio waves of the problem are within the range 188-545 m.