Answer:
Radius between electron and proton
Explanation:
The motion of the electron is carried out in the orbit due to the balancing of the electrostatic force between the proton and the electron and the centripetal force acting on the electron.
The electrostatic force is given as = 
Where,
k = coulomb's law constant (9×10⁹ N-m²/C²)
q₁ and q₂ = charges = 1.6 × 10⁻¹⁹ C
r = radius between the proton and the electron
Also,
Centripetal force on the moving electron is given as:
=
where,
= mass of the electron (9.1 ×10⁻³¹ kg)
V = velocity of the moving electron (given: 6.1 ×10⁵ m/s)
Now equating both the formulas, we have
= 
⇒
substituting the values in the above equation we get,

⇒
Answer:
a. an increase in the mass on the spring.
Explanation:
An increase in the mass on the spring will increase the period of an oscillating spring mass system.
Mathematically, the period of an oscillating spring mass system is given by the formula;
T = 2π √(m/k)
Where;
T is the period.
m is the mass of the spring.
k is the spring constant.
Hence, the mass of a spring is directly proportional to the period of oscillation of the spring.
This ultimately implies that, as the mass of the spring increases, the period of oscillation will increase. Similarly, the period of oscillation will decrease with an increase in the spring constant.
The minimum frequency is

while the maximum frequency is

Using the relationship between frequency f of a wave, wavelength

and the speed of the wave v, we can find what wavelength these frequencies correspond to:


So, the wavelengths of the radio waves of the problem are within the range 188-545 m.