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umka2103 [35]
3 years ago
12

The air pressure inside a car tire is

Physics
1 answer:
Valentin [98]3 years ago
7 0

Answer:

0.137m²

Explanation:

Pressure = Force/Area

Given

Force = 41,500N

Pressure = 3.00atm

since 1atm = 101325.00 N/m²

3atm = 3(101325.00)

3atm = 303,975N/m²

Pressure = 303,975N/m²

Get the area

Area = Force/Pressure

Area = 41500/303,975

Area = 0.137m²'

Hence the surface area of the  inside of the tire is 0.137m²

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A block with a mass of 31.8 kg is pushed on a frictionless
OlgaM077 [116]

Answer: Total work done on the block is 3670.5 Joules.

Step by step:

Work done:

W = F.d.\cos\theta

With F the force, d the displacement, and theta the angle of action (which is 0 since the block is pushed along the direction of displacement, and cos 0 = 1)

W = F.d

Given:

F = 75 N

m = 31.8 kg

Final velocity v_f = 15.3 \frac{m}{s}

In order to calculate the Work we need to determine the displacement, or distance the block travels. We can use the information about F and m to first figure out the acceleration:

F = ma\\\implies a=\frac{F}{m}=\frac{75 N }{31.8 kg}\approx 2.36 \frac{m}{s^2}\\

Now we can determine the displacement from the following formula:

d = \frac{1}{2}a^2+v_0t+d_0

Here, the initial displacement is 0 and initial velocity is also 0 (at rest):

d = \frac{1}{2}at^2\\

Now we still have "t" as unknown. But we are given one more bit of information from which this can be determined:

v_f = a\cdot t_f\\\implies t_f = \frac{v_f}{a} = \frac{15.2 \frac{m}{s}}{2.36 \frac{m}{s^2}}\approx 6.44 s

(using vf as final velocity, and tf as final time)

So it takes about 6.44 seconds for the block to move. This allows us to finally calculate the displacement:

d = \frac{1}{2}at^2=\frac{1}{2}2.36 \frac{m}{s^2}\cdot 6.44^2 s^2 \approx 48.94 m

and the corresponding work:

W = F\cdot d=75 N\cdot 48.94 m =3670.5J


7 0
3 years ago
An electron moving horizontally to the right with speed v enters a region where a uniform magnetic field exists pointing into th
koban [17]

Answer:

W = 0

Explanation:

When an electron moves perpendicular to a uniform B-field. If the field is in a vacuum, the magnetic field B is the dominant factor determining the motion. Since the magnetic force F is perpendicular to the direction of travel, an electron follows a curved path in a magnetic field. The electron continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force F is always perpendicular to velocity v, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.

W = F*d*Cos ∅ = F*d*Cos 90° = 0  where d is the displacement.

The pic shown can help to understand the explanation.

5 0
3 years ago
A clothing store has sensors that track how many people enter the store and cash registers that track how many purchases people
Ksivusya [100]

This information is valuable because Managers can use this customer data each month to figure out whether a larger or smaller percentage of visitors are buying clothes there.

<h3>What is the percentage of a number?</h3>

It is the relative value that represents the hundredth part of any number for example 2% of any number represents, 2 multiplied by the 1/100th of that number.

A clothes business contains sensors that count the number of customers entering the store and cash registers that count the number of transactions made daily.

Thus, data is useful because Managers may use it to determine if a greater or lesser proportion of customers are purchasing clothing each month. Therefore the correct answer is option A.

Learn more about the percentage here,

brainly.com/question/24159063

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8 0
1 year ago
A photographer uses his camera, whose lens has a 50 mm focal length, to focus on an object 2.5 m away. He then wants to take a p
Temka [501]

Answer:

0.004 m away from the film

Explanation:

u = Object distance

v = Image distance

f = Focal length = 50 mm

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{0.05}-\frac{1}{2.5}\\\Rightarrow \frac{1}{v}=\frac{98}{5} \\\Rightarrow v=\frac{5}{98}=0.051\ m

The image distance is 0.051 m

When u = 50 cm

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{0.05}-\frac{1}{0.5}\\\Rightarrow \frac{1}{v}=18\\\Rightarrow v=\frac{1}{18}=0.055\ m

The image distance is 0.055 m

The lens has moved 0.055-0.051 = 0.004 m away from the film

3 0
3 years ago
In a bicycle dynamo,does 1. The permanent magnet surrounds a conducting coil 2. The conducting coil rotates when the rear wheel
atroni [7]

Explanation:

3: the electricity is generated in the permanent magnet

7 0
3 years ago
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