The problem you have written you almost have it solved. Take the moles that you have calculated and multiply that by the molecular weight to get the grams.
The STP problem:
use the moles you calculated along with 1 atm for Pressure, and 273 for the temperature and plug into the PV = nRT equation. (also use 0.0821 for R)
From there you can solve for the volume
Hope this helps!
2. Rubidium
3. Antimony
4. Ytterbium
5. Einsteinium
Answer:
55.75g
Explanation:
From
m/M = CV
Where
m= required mass of solute
M= molar mass of solute
C= concentration of solution
V= volume of solution=675ml
Molar mass of solute= 3(23) + 31 + 4(16)= 69+31+64=164gmol-1
Number of moles of sodium ions present= 1.5× 675/1000= 1.01 moles
Since 1 mole of Na3PO4 contains 3 moles of Na+
It implies that 1.01/3 moles of Na3PO4 are present in solution= 0.34moles
mass of Na3PO4= number of moles × molar mass= 0.34 × 164 =55.75g
I think the answe would be 16n
Answer : The given statement is, false.
Explanation :
Ionic product of water : It is defined as the product of the concentration of hydrogen ion and the concentration of hydroxide ion.
The mathematical expression will be,
![[H^+][OH^-]=10^{-14}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%5BOH%5E-%5D%3D10%5E%7B-14%7D)
When the concentration of hydrogen ion and hydroxide ion are equal then the solution is neutral and the value will be, 
. And the pH of the solution is, 7.
When the concentration of hydrogen ion is greater than then the solution is acidic in nature. And the pH of the solution is, less than 7.
When the concentration of hydrogen ion is less than then the solution is basic in nature. And the pH of the solution is, greater than 7.
Hence, the given statement is false.
