Answer:
False
Explanation:
The ideas were not proposed
Answer:- 171 g
Solution:- It asks to calculate the grams of sucrose required to make 1 L of 0.5 Molar solution of it.
We know that molarity is moles of solute per liter of solution.
If molarity and volume is given then, moles of solute is molarity times volume in liters.
moles of solute = molarity* liters of solution
moles of solute = 0.5*1 = 0.5 moles
To convert the moles to grams we multiply the moles by molar mass.
Molar mass of sucrose = 12(12) + 22(1) + 11(16)
= 144 + 22 + 176
= 342 grams per mol
grams of sucrose required = moles * molar mass
grams of sucrose required = 0.5*342 = 171 g
So, 171 g of sucrose are required to make 1 L of 0.5 molar solution.
Answer:
B. chemical
Explanation:
Chemical change cannot go back to its original form
Answer:
0.779 cube centimetres
Explanation:
density = mass divided by volume
rearrange the equation to solve for volume: 
plug in the corresponding values:
volume = 6.130 g / 7.87 (gcm^3)
the gs cancel, the answer will be 0.7789
we will round to three sig figs, since that's the lowest amount of figures in the given values: ~0.779 cm^3
We are given that:
100 mL total solution with 1:50 povidone iodine solution
This means that there is 1 mL of povidone iodine solution
per 50 mL of total solution. Since we are given a total of 100 mL solution,
therefore we have an initial amount of:
pure povidone iodine solution = 2 mL
This amount of pure povidone iodine solution is added or
diluted (most perhaps with water) to make a total of 1000 mL total solution,
therefore the new ratio is:
2:1000 povidone iodine solution
By dividing both sides by 2, this simplifies to
1:500 povidone iodine solution
Answer:
1:500
