The surface area of the first figure is 160.
The net of the second figure is attached, and the surface area is 408.
To find the surface area of the first figure, we find the area of the base:
10*10 = 100
Now we find the area of each of the 4 lateral faces (triangles):
A=1/2bh = 1/2(3)(10) = 15
The total is 100+15(4) = 160
To find the surface area of the second figure, find the area of the bases (triangles):
A=1/2bh = 1/2(6)(8)= 24
The area of the bottom lateral face is 15*6 = 90.
The area of the slanted lateral face is 15*10 = 150.
The area of the vertical lateral face is 15*8 = 120.
Together we have 24(2) + 90 + 150 + 120 = 408.
The net of the second figure is attached, and the surface area is 408.
To find the surface area of the first figure, we find the area of the base:
10*10 = 100
Now we find the area of each of the 4 lateral faces (triangles):
A=1/2bh = 1/2(3)(10) = 15
The total is 100+15(4) = 160
To find the surface area of the second figure, find the area of the bases (triangles):
A=1/2bh = 1/2(6)(8)= 24
The area of the bottom lateral face is 15*6 = 90.
The area of the slanted lateral face is 15*10 = 150.
The area of the vertical lateral face is 15*8 = 120.
Together we have 24(2) + 90 + 150 + 120 = 408.