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3 years ago

What is 15 x 3/5 =? Thank you

Mathematics

2 answers:

tekilochka [14]3 years ago

8 0

Answer:

1-first place the numbers like this

15/1 ×3/5

2- do 15×3 with is 45

3- then 1×5 which is 5

4- then divide 45÷5 which is 9

The answer is 9

ipn [44]3 years ago

4 0

15 x 3/5

Cross out 15 and 5 . Divide by 5 .

15/5=3

3/3=1

3*3/1

3*3=9

Answer: 9

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Answer:

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3 years ago

hat are the solutions to the equation |x| = 2? Choose all answers that are correct. A. B. C. D.

zalisa [80]

Easy, so absolute value makes anything inside into positive
|x|=2
therefor x=-2 or x=2 since it would be made posotive

answer is -2 and 2

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3 years ago

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What is the nth term rule of the quadratic sequence below?<br> 8,14,22,32 ,44, 58, 74...

DanielleElmas [232]

Answer:

y=n^2+3n+4

Step-by-step explanation:

Sequence,S: 8,14,22,32 ,44, 58, 74...

First differences of S: 6,8,10,12,14,16,...

Second differences of S: 2,2,2,2,2,2,....

It is indeed a quadratic since the 1st differences that are the same are the second differences.

So the 1st term is 8. If the 0th term was listes it would be 4 since 8-4=4 and 6-4=2.

This means our quadratic it is in the form

y=an^2+bn+c where c=4.

So we have y=an^2+bn+4.

Now we can find a and b using two points from our sequence to form a system of equations to solve.

(1,8) gives us 8=a(1)^2+b(1)+4

Simplifying gives 8=a+b+4

Subtracting 4 on both sides gives: 4=a+b

(2,14) gives us 14=a(2)^2+b(2)+4

Simplifying gives 14=4a+2b+4

Subtracting 4 on both sides gives 10=4a+2b

So we have the following system to solve:

4=a+b

10=4a+2b

I'm going to solve using elimination/linear combination style.

Dividing second equation by 2 gives the system as:

4=a+b

5=2a+b

Subtract the 2nd equation from the first gives:

-1=-1a

This implies a=1 since -1=-1(1) is true.

If a+b=4 and a=1, then b=3. Because 3+1=4.

So the equation is y=1n^2+3n+4 or y=n^2+3n+4.

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3 years ago

6. a. Name a pair of equations that have exactly one point of intersection. How do you know?

True [87]

Answer:

A system of linear equations will have exactly one point of intersection, for example:

2x+y=5

-x+y=2

However, a system of linear equations with no solution will have no points of intersection, for example:

-4x+10y=6

2x-5y=3

Sorry about c. though I'm confused on how a pair of equations can have infinite points of intersection unless x or y equals all real numbers which could happen if x or y both equaled all real numbers maybe

And the point of interesection for the system of equations in the problem you attached as an image is (2,-1)

I attached a photo below, and one of how to graph it

4 0

3 years ago

Which congruence theorems can be used to prove △EFG ≅ △JHG? Check all that apply.

sasho [114]

Answer:

ASA and AAS

Step-by-step explanation:

We do not know if these are right triangles; therefore we cannot use HL to prove congruence.

We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.

We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.

Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.

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3 years ago

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