Answer:
We need a sample of at least 1797 if we wish to be 95% confident that the sample percentage of those equating success with personal satisfaction is within 2.3% of the population percentage.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
In this problem, we have that:

How large a sample is needed if we wish to be 95% confident that the sample percentage of those equating success with personal satisfaction is within 2.3% of the population percentage?
We have to find n for which
. So







We need a sample of at least 1797 if we wish to be 95% confident that the sample percentage of those equating success with personal satisfaction is within 2.3% of the population percentage.
The given points are the vertices of the quadrilateral

By Green's theorem, the line integral is


Answer:104
Step-by-step explanation:
104+75=180
Answer:
the correct answer is 8,000ft
Step-by-step explanation:
sin30°=4000ft/h
hsin30°=4000ft
h=4000ft/sin30°
h= 8,000ft