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11Alexandr11 [23.1K]
4 years ago
8

Solving Systems of Linear Equations by graphing. 3y+4x=3 and x+3y=-6. Can someone help me with where the lines intersect and sho

w me how they solved it on paper? I keep getting it wrong even though i think its right but i just need a second opinion
Mathematics
1 answer:
Greeley [361]4 years ago
8 0
The best way to do this question is to use elimination. Elimination is a way to find out the POINT OF INTERSECTION between two lines. Let me show you how.

3y+4x=3
x+3y=-6

Elimination is a way to remove any same variable with the same coefficient. In this case, there is 3y in both equations. In this case, we subtract to eliminate.

3y-3y+4x-x=3+6  It's plus 6 because two negatives become positive.
3x=9  Divide both sides by 3
x=3

Now you can find y.

x+3y=-6
3+3y=-6
3y=-9
y=-3

Therefore, the POI is (3,-3). I hope you understand this. Make sure to mark as brainliest.
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Numerical expressions:(I need help)<br> 1.) x-27=(-14) x=?<br> 2.) x-72=12 x=?<br> 3.) x*12=60 x=?
tensa zangetsu [6.8K]

1).  Add 27 to each side of the equation.

2). Add 72 to each side of the equation.

3). Divide each side of the equation by 12.

5 0
4 years ago
In the diagram, AB is a tangent to the circle, centre O. D is the mid-point of the chord BC. Given that BAC = x, find COD in the
Westkost [7]

Answer:

\angle COD =\frac{90+x}{2} in term of x

Step-by-step explanation:

Given that AB is tangent to a circle with center O and radius of OC=OB

D is the mid-point of the chord BC and D is 90

Here, Angle BAC = x.

From figure,

AC is a straight line.

we can write as

\angle AOB+\angle BOD +\angle COD =180

Since D is the mid-point of the chord BC

We know,

Angle opposite to sides are congruent

\angle BOD=\angle COD

So,

\angle AOB+\angle BOD +\angle COD =180

\angle AOB +2\angle COD =180

Now, In triangle AOB

\angle ABO = 90

Therefore,

\angle AOB+\angle ABO+\angle BAO=180

\angle AOB=90-x

Therefore.

\angle AOB +2\angle COD =180

(90-x) +2\angle COD =180

-x+2\angle COD =90

2\angle COD =90+x

\angle COD =\frac{90+x}{2}

Thus, \angle COD =\frac{90+x}{2}

6 0
4 years ago
Claim: The standard deviation of pulse rates of adult males is less than 11 bpm. For a random sample of 132 adult​ males, the pu
seraphim [82]

Answer:

\chi^2 =\frac{132-1}{121} 114.49 =123.952

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=132 represent the sample size

\alpha represent the confidence level  

s^2 =10.7^2 =114.49 represent the sample variance obtained

\sigma^2_0 =11^2=121 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is violated, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 121

Alternative hypothesis: \sigma^2

Calculate the statistic  

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{132-1}{121} 114.49 =123.952

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 131. And since is a right tailed test the p value would be given by:

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(123.952,131,TRUE)"

5 0
3 years ago
7c - 7 = 4c + 17 *has to show work*
Nina [5.8K]
7c-7=4c+17
7c-4c=17+7
3c=24
c=24/3=8
6 0
4 years ago
A rectangle field is 120 yards long and 85 yards wide
Sphinxa [80]

The area of this rectangle:

120yd × 85yd = 10200yd²

3 0
3 years ago
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