3 years ago

What is the equation of the line that passes through the point (-5,5) and has a slope of -1

Mathematics

1 answer:

max2010maxim [7]3 years ago

7 0

Answer:

y - 5 = -(x + 5)

y - 5 = -x - 5

y = -x

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If K is the midpoint of JL, JK = 8x+11 and KL = 14x-1, find JL.

gladu [14]

Step-by-step explanation:

Since, K is the midpoint of JL.

$\therefore \: JK = KL \\ 8x + 11 = 14x - 1 \\ 11 + 1 = 14x - 8x \\ 12 = 6x \\ \frac{12}{6} = x \\ 2 = x \\ \\ \because \: JL = JK + KL \\ \therefore \: JL = 8x + 11 + 14x - 1 \\ \therefore \: JL = 8x + 14x + 11 - 1 \\ \therefore \: JL = 22x + 10\\ \therefore \: JL = 22 \times 2 + 10..(plug \: x = 2) \\ \therefore \:JL = 44 + 10 \\ \huge \red{ \boxed{\therefore \:JL = 54}}$