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2 years ago

11

If you need to measure the mass of a greeting card you are sending to a friend through the mail, what unit of measurement would

you use

1 answer:

erica [24]2 years ago

4 0

You would use grams to measure ot

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Los materiales sinteticos tienen implicaciones en el medio ambiente

svp [43]

Answer:

no

Explanation:

los materiales sinteticos son aquellos materiales q estan hechos de polimeros sintetilizados o de pequeñas moleculas

6 0

2 years ago

The three major types of faults are normal, reverse and syncline. true or false

Novosadov [1.4K]

The three major types of faults are Normal, Reverse and Strike-slip faults.

Answer: FALSE

6 0

2 years ago

Read 2 more answers

Write balanced reactions for the complete combustion of hydrogen. Express your answer as a chemical equation. Identify all of th

Fantom [35]

Answer:

Explanation:

A combustion involves the reaction of a fuel with oxygen (O₂). During the reaction of combustion of hydrogen (H₂), H₂ reacts with O₂ to form water (H₂O). The <em>balanced chemical equation</em> is the following:

2 H₂(g) + O₂(g) → 2 H₂O(g)

According to the chemical equation, 2 moles of H₂O are obtained from the reaction of 2 moles of H₂ with 1 mol of O₂. All reactants and products are in the gaseous phase.

7 0

2 years ago

The most common source of copper (cu) is the mineral chalcopyrite (cufes2). how many kilograms of chalcopyrite must be mined to

tigry1 [53]

Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

Solution : Given,

Mass of Cu = 300 g

Molar mass of Cu = 63.546 g/mole

Molar mass of $CuFeS_2$ = 183.511 g/mole

First we have to calculate the moles of Cu.

$\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles$

The moles of Cu = 4.7209 moles

From the given chemical formula, $CuFeS_2$ we conclude that the each mole of compound contain one mole of Cu.

So, The moles of Cu = Moles of $CuFeS_2$ = 4.4209 moles

Now we have to calculate the mass of $CuFeS_2$ .

Mass of $CuFeS_2$ = Moles of $CuFeS_2$ × Molar mass of $CuFeS_2$ = 4.4209 moles × 183.511 g/mole = 866.337 g

Mass of $CuFeS_2$ = 866.337 g = 0.8663 Kg (1 Kg = 1000 g)

Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

3 0

2 years ago

The acid dissociation constant ka for an unknown acid ha is 4.57 x 10^-3 what is the base dissociation constant kb for th econju

SashulF [63]

Answer:

2.19 x 10^-12.

Explanation:-

The relation between Ka and Kb for an acid and it's conjugate base is

Ka x Kb = Kw where Kw = ionic product of water.

So Kb = 10^-14 / (4.57 x 10 ^ -3)

= 2.19 x 10^-12

4 0

2 years ago