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mr_godi [17]
3 years ago
14

What molecule is responsible for chemical digestion.

Chemistry
1 answer:
padilas [110]3 years ago
8 0

Answer:

Amylase.

Explanation:

The process of digestion begin to start in mouth when food mix with saliva. An enzyme is released which is called Amylase help in digestion of carbohydrates.

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Does anyone know how to do common ion effect in chemistry?
pishuonlain [190]

Answer:

no i do not sorry for you

7 0
3 years ago
The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.
atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M  

Explanation:

<u>The photodissociation of ozone by UV light is given by:</u>

O₃ + hν → O₂ + O (1)

<u>The first-order reaction of the equation (1) is:</u>

rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t} (2)

<em>where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration </em>    

<u>We can get the following expression of the </u><u>first-order integrated law</u><u> of the reaction (1), by resolving the equation (2):</u>

[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt} (3)

<em>where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration</em>

We can calculate the initial ozone concentration using equation (3):  

[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!                    

3 0
3 years ago
A block of aluminum occupies a volume of 15.0 cm and weighs 40.5 g. What is its density?
mafiozo [28]

Answer:

2.7 g/cm^3

Explanation:

D = m/V

D = 40.5 g / 15 cm^3

D =  2.7 g/cm^3

7 0
3 years ago
Please help me it's a emergency!!!!!​
PilotLPTM [1.2K]

Answer:

probably a space probe because the sun is too hot for anything else to go on  the sun

Explanation:

8 0
3 years ago
What pressure in atmospheres(atm) is equal to 45.6 kPa?
postnew [5]
1 kpa = 0.0098692327 atm so just multiply that by 45.6
4 0
3 years ago
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