Answer:
The n th of the given sequence is 
Step-by-step explanation:
<u>Step 1</u> :-
Given sequence is 20,14,8,2,.......this sequence in arithmetic progression but this sequence is decreasing sequence.
given first term is 20 and difference is
now the nth term of given sequence is
by using formula 


final answer:-

<u>verification</u>:-

put n=1 we get first term is 20
put n=2 we get second term is 14
put n=3 we get third term is 8
put n=4 we get fourth term is 2
so the n th term of sequence is

Answer:Find the distance between the parallel lines m and n whose equations are y = x + 4 and y = x - 6, respectively.
There are several ways to do this...here's one
Let (0, 4) be a point on the first line
Then.......a line with a negative reciprocal slope going through this point will have the equation :
y = -x + 4........so......we can find the intersection of this line with y = x - 6....set both equations equal
-x + 4 = x - 6 add x, 6 to both sides
10 = 2x divide both sides by 2
5 = x
So...using -x + 4, the y value at intersection = -1.......
So...we just need to find the distance from (0,4) to ( 5, -1) =
√[ (5)^2 + (4 + 1)^2 ] = 5√2 ≈ 7.07 units
Here's a pic....AB is the distance with A = (0,4) and B = (5, -1)
Step-by-step explanation:
Answer:
Step-by-step explanation:
D.All of the above
Answer:
f(x)= $70 - $1.5*x
Step-by-step explanation:
You know your friend spends $ 5 to enter the fair and $ 15 for food. So the total you spent is given by:
$5 + $15= $20
Knowing that the trips at the fair cost $ 1.50 per trip, and with x being the number of trips, then the cost after x trips will be:
$1.5*x
So the money spent after x rides can be expressed as:
$20 + $1.5*x
Knowing that your friend has $90 when he goes to the fair, to calculate the amount of money he has left after x rides, the amount taken to the fair and the amount spent is subtracted:
$90 - ($20 + $1.5*x)
$90 -$20 -$1.5*x
$70 - $1.5*x
By calling the function f(x) used to determine the amount of money left after x trips, you can finally express:
<u><em>f(x)= $70 - $1.5*x</em></u>