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galina1969 [7]
3 years ago
6

Help me out please? Show some type of work along with your explanation.

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0
Name's that can be applied to the quadrilateral in the figure given.

★ Parallelogram

By the figure we can see that the opposite sides are equal and parallel.
And by this we can also conclude that the opposite angles are equal.
So, by this we can say that the figure is of a parallelogram.

★ Rhombus

Rhombus have all sides equal and opposite sides parallel.
And opposite angles equal.
So, by this we can say that the figure is of Rhombus.

Hope this helps!
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I equals 3.14, T equals 5.71, P equals three years. <br><br> I divided by T divided by P equals?
Lunna [17]
3.14/5.71=0.18330414466 years hope this hepls
5 0
3 years ago
Suppose y varies directly as x, and y =15 when x = 3. Find the constant of variation (k).
vovangra [49]

Answer:

k = 5

Step-by-step explanation:

y = kx

15 = k(3)

k = 15/3

k = 5

8 0
3 years ago
Which statement is true about the measures of the interior angles of a triangle?
stellarik [79]

Answer:

B

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Evaluate x+16, when x=8
Hatshy [7]

Answer:

24

Step-by-step explanation:

x + 16

8 + 16

= 24

You just plug in 8 in the x place. Hope this helps, thank you !!

7 0
3 years ago
Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th
11111nata11111 [884]

Answer:

The null hypothesis is H_0: \mu = 14

The alternate hypothesis is H_a: \mu < 14

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

H_0: \mu = 14

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

H_a: \mu < 14

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \mu = 14

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that n = 40

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}

t = -1.95

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

5 0
2 years ago
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