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Novay_Z [31]
4 years ago
10

The only force acting on a 2.9 kg canister that is moving in an xy plane has a magnitude of 7.5 N. The canister initially has a

velocity of 3.9 m/s in the positive x direction, and some time later has a velocity of 5.1 m/s in the positive y direction. How much work is done on the canister by the 7.5 N force during this time?
Physics
1 answer:
Elodia [21]4 years ago
7 0

Answer:15.66 J

Explanation:

mass of block \left ( m\right )=2.9 kg

Force magnitude=7.5 N

Initial velocity =3.9\hat{i} m/s

Final velocity=5.1 \hat{j} m/s

Initial Kinetic Energy=\frac{1}{2}mv^2

=\frac{1}{2}\times 2.9\times 3.9^2=22.05 J

Final Kinetic Energy=\frac{1}{2}mv^2

=\frac{1}{2}\times 2.9\times 5.1^2=37.714 J

Work Done =Final -Initial Kinetic energy=37.714-22.056=15.66 J

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What are the primary differences between stars and planets
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If the mass of an object is 14 lbm, what is its weight, in lbf, at a location where g = 32.0 ft/s2?
mixas84 [53]

Using the formula:

w = m x g ....... eq1

here w is weight of the object.

m is mass of the object, and

g is the acceleration of gravity.

mass, m = 14 lbm (given)

acceleration of gravity, g= 32.0 ft/s^{2}

Now, substituting the values in equation (1):

w = 14lbm x 32.0 ft/s^{2} = 448 lbm ft/s^{2}

since, 1 lbf = 32.174 lbm ft/s^{2}

so, w = 448 x \frac{1}{32.174}

w = 13.924lbf

Hence, the mass of an object is 13.924 lbf.

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3 0
2 years ago
This is a graph of a marble traveling across a smooth surface. What is the average speed of this marble?
prohojiy [21]
Since it is a smooth marble and basing from the graph, it has a constant slope, you could just get any two points along the line and get its slope since speed is Δd/Δt. Let the points be (4,6) and (6,9). Thus,

Δd/Δt = (9-6)/(6-4) = 1.5

Thus, the average speed is 1.5 m/s.
7 0
4 years ago
Read 2 more answers
The 20 g bullet is traveling at 400 m/s when it becomes embedded in the 2 -kg stationary block. Determine the distance the block
Marina CMI [18]

Answer:

The block+bullet system moves 4 m before being stopped by the frictional force.

Explanation:

Using the law of conservation of llinear momentum and the work energy theorem, we can obtain this.

According to Newton's second law of motion

Momentum before collision = Momentum after collision

Momentum before collision = (0.02×400) + 0 (stationary block)

Momentum before collision = 8 kgm/s

Momentum after collision = (2+0.02)v

8 = 2.02v

v = 3.96 m/s.

According to the work-energy theorem,

The kinetic energy of the block+bullet system = work done by Friction to stop the motion of the block+bullet system

Kinetic energy = (1/2)(2.02)(3.96²) = 15.84 J

Work done by the frictional force = F × (distance moved by the force)

F = μmg = 0.2(2.02)(9.8) = 3.96 N

3.96d = 15.84

d = (15.84/3.96) = 4 m

5 0
3 years ago
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