Answer:
v = 3.81 m/s
Explanation:
First, we will find out the radius (r)
sinΘ = r / L
or
r = LsinΘ
on substituting the values, we get
r = 1.2 × sin18°
or
r = 0.370 m
Now,
The tension (T) can be calculated as
ΣF(y) = 0
or
Tcos18° - mg = 0
or
T = mg / cos18.8°
on substituting the values, we have
T = (2kg x 9.8m/s²) / cos18°
or
T = 20.60 N
Now, applying the equilibrium condition in horizontal direction. we have
also, the centripetal acceleration 
on substituting the values, we get
m(v² / r) = Tsin18°
v = (rTsin18° / m)
v = [(1.2m)(20.60 × sin18°) / 2kg]
v = 3.81 m/s
- According to Newton's Third Law of Motion, to every action, there is an equal and opposite reaction; action and reaction act on different bodies.
- Here, the action force is in the leftward direction, so the reaction will be in the opposite direction.
- If the action force is the swimmer pushing water in the leftward direction, then the reaction force is in the rightward direction.
- And the reaction force will be given by the water on the swimmer.
<u>Answer</u><u>:</u>
<u>The </u><u>reaction </u><u>force </u><u>is </u><u>the </u><u>water </u><u>pushing </u><u>the </u><u>swimmer </u><u>in </u><u>the </u><u>rightward </u><u>direction</u><u>.</u>
Hope you could get an idea from here.
Doubt clarification - use comment section.
Energy is the capacity for doing work..
Kinetic energy - Moving car
Potential energy - flowing water up the hill
The correct answer is compound
I think this is correct, but I am not entirely certain.
Find the force constant of the spring:
F = - KX
(0 - 62.4) = -K(0.172m)
-362.791 = -K
362.791 N/m = K
Find the work done in stretching the spring:
W = (1/2)KX
W = (1/2)(362.791)(0.172m)
W = 31.2 J
