What are the primary differences between stars and planets

Physics

2 answers:

Sergio039 [100]2 years ago

7 0

Stars aren't big enough to emit enough kight and heat meaning they cant cause nuclear reactions

shusha [124]2 years ago

6 0

Stars don't have moons and planets do

You might be interested in

In a bi-prism experiment the eye-piece was placed at a distance 1.5m from the source. The distance between the virtual sources w

Vladimir [108]

Answer:

λ = 1.4 × 10^(-7) m

Explanation:

We are given;

distance of eye piece from the source;D = 1.5 m

distance between the virtual sources;d = 7.5 × 10^(-4) m

To find the wavelength, we will use the formula for fringe width;

X = λD/d

Where X is fringe width, λ is wavelength, while d and D remain as before.

Now, fringe width = eye-piece distance moved transversely/number of fringes

Eye piece distance moved transversely = 1.88 cm = 1.88 × 10^(-2) m

Thus,

Fringe width = (1.88 × 10^(-2))/10 = 1.88 × 10^(-3) m

Thus;

1.88 × 10^(-3) = λ(1.5)/(7.5 × 10^(-4))

λ = [1.88 × 10^(-3) × (7.5 × 10^(-4))]/1.5

λ = 1.4 × 10^(-7) m

6 0

3 years ago

Which kind of waves is not part of the electromagnetic spectrum?

Dennis_Churaev [7]

The answer is radio waves

5 0

2 years ago

Question 2 10

ss7ja [257]

B Ik it all just know who they’ll you

8 0

2 years ago

BRAINLIST A wave travels at a constant speed. How does the wavelength change if the

Studentka2010 [4]

I think it will be (c)

3 0

2 years ago

At the race track, one race car starts its engine with a resulting intensity level of 104.0 dB at point P. Then 6 more cars star

dem82 [27]

To solve the problem it is necessary to apply the concepts related to sound intensity. The most common approach to sound intensity measurement is to use the decibel scale:

$\beta (dB) = 10log_{10}(\frac{I}{I_0})$

Where,

$I_0 = 1*10^{-12}$ is a reference intensity. It is the lowest or threshold intensity of sound a person with normal hearing can perceive at a frequency of 1000 Hz.