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ZanzabumX [31]
3 years ago
14

A 45.0-N force pushes a cart 12.5 meters down a hallway. What is the work done on the cart?

Physics
1 answer:
makvit [3.9K]3 years ago
3 0

Answer:

562.5J

Explanation:

The following were obtained from the question:

F = 45N

d = 12.5m

w =?

The work done can be achieved by using

w = F x d

w = 45 x 12.5

w = 562.5J

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First the amount of work done in lifting up the snow ball to a height of 1.2m is equal to the potential energy of the ball after the lift.

Therefore mass× gravitational pull×height will give us the work done

=3.2kg ×9.8N/kg×1.2m

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=1.0N×25m

=25J

On reaching the headless snowman you have to lift the ball a further 1.1m to place it as the head 2.3m high.

therefore this will be a change in potential energy which is equal to work done in lifting the ball the additional 1.1m

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=3.2kg×9.8N/kg×1.1m

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Suppose a scientist doing an experiment in nuclear fusion starts out with twelve atoms. How many atoms will most likely result f
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Date the law of conversation of energy
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In its most compact form, it states: matter is neither created nor destroyed. In 1842, Julius Robert Mayer discovered the Law of Conservation of Energy.

Explanation:

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Based on its type of chemical bond, which of the following has the highest boiling point?
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<h3><u>Answer;</u></h3>

Potassium chloride

<h3><u>Explanation;</u></h3>
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A cart starts at x = +6.0 m and travels towards the origin with a constant speed of 2.0 m/s. What is it the exact cart position
Ira Lisetskai [31]

Answer:

At the origin (x' = 0 m)

Explanation:

Note: From the question, when the cart travels towards the origin, the magnitude of its exact position reduces with time.

The formula of speed is given as

S = d/t................. Equation 1

Where S = speed of the cart, d = distance covered by the cart over a certain time. t = time taken to cover the distance.

make d the subject of the equation,

d = St ................. Equation 2

Given: S = 2.0 m/s, t = 3.0 s

Substitute into equation 2

d = 2(3)

d = 6 m.

From the above, the cart covered a distance of 6 m in 3 s.

The exact position of the cart = Initial position-distance covered

x' = x-d............ Equation 3

Where x' = exact position of the cart 3 s later, x = initial position of the cart, d = distance covered by the cart in 3.0 s.

Given: x = +6.0 m, d = 6 m.

Substitute into equation 3

x' = +6-6

x' = 0 m.

Hence the cart will be at 0 m (origin) 3 s later

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3 years ago
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