Answer:
The mass of the baked loaf will be less than the dough.
Explanation: When heat is applied to food substance or products like the one pound the substance or material gains a higher temperature, the increase in temperature causes moisture inherent or added to the product in this case the one pound dough to be lost, the one pound dough prepared at room temperature, once it is placed inside the oven at 350 degrees Fahrenheit it will lose moisture in the form of vapor to the environment as noticed in the aroma, the moisture lost will eventually reduce it mass/weight (kilograms or grams) by some percentage or quantities(kilograms or grams)
Answer:
Explanation:
Given
1 mole of perfect, monoatomic gas
initial Temperature![(T_i)=300 K](https://tex.z-dn.net/?f=%28T_i%29%3D300%20K)
![P_i=10 atm](https://tex.z-dn.net/?f=P_i%3D10%20atm)
![P_f=2 atm](https://tex.z-dn.net/?f=P_f%3D2%20atm)
Work done in iso-thermal process![=P_iV_iln\frac{P_i}{P_f}](https://tex.z-dn.net/?f=%3DP_iV_iln%5Cfrac%7BP_i%7D%7BP_f%7D)
=initial pressure
=Final Pressure
![W=10\times 2.463\times ln\frac{10}{2}=39.64 J](https://tex.z-dn.net/?f=W%3D10%5Ctimes%202.463%5Ctimes%20ln%5Cfrac%7B10%7D%7B2%7D%3D39.64%20J%20)
Since it is a iso-thermal process therefore q=w
Therefore q=39.64 J
(b)if the gas expands by the same amount again isotherm-ally and irreversibly
work done is![=P\Delta V](https://tex.z-dn.net/?f=%3DP%5CDelta%20V)
![V_1=\frac{RT_1}{P_1}=\frac{1\times 0.0821\times 300}{10}=2.463 L](https://tex.z-dn.net/?f=V_1%3D%5Cfrac%7BRT_1%7D%7BP_1%7D%3D%5Cfrac%7B1%5Ctimes%200.0821%5Ctimes%20300%7D%7B10%7D%3D2.463%20L)
![V_2=\frac{RT_2}{P_2}=\frac{1\times 0.0821\times 300}{2}=12.315 L](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7BRT_2%7D%7BP_2%7D%3D%5Cfrac%7B1%5Ctimes%200.0821%5Ctimes%20300%7D%7B2%7D%3D12.315%20L)
![\Delta W=1\times (12.315-2.463)=9.852 J](https://tex.z-dn.net/?f=%5CDelta%20W%3D1%5Ctimes%20%2812.315-2.463%29%3D9.852%20J)
![\Delta q=\Delta W=9.852 J](https://tex.z-dn.net/?f=%5CDelta%20q%3D%5CDelta%20W%3D9.852%20J)
![\Delta U=0](https://tex.z-dn.net/?f=%5CDelta%20U%3D0)
Answer:
A) The wave that travels through the rail reaches the microphone first.
B) separation in time between the arrivals of the two pulses is 0.01539 seconds.
Explanation:
Detailed explanation and calculation is shown in the image below
Answer:
Length of the pipe = 53.125 cm
Explanation:
given data
harmonic frequency f1 = 800 Hz
harmonic frequency f2 = 1120 Hz
harmonic frequency f3 = 1440 Hz
solution
first we get here fundamental frequency that is express as
2F = f2 - f1 ...............1
put here value
2F = 1120 - 800
F = 160 Hz
and
Wavelength is express as
Wavelength = Speed ÷ Fundamental frequency ................2
here speed of waves in air = 340 m/s
so put here value
Wavelength =340 ÷ 160
Wavelength = 2.125 m
so
Length of the pipe will be
Length of the pipe = 0.25 × wavelength ......................3
put here value
Length of the pipe = 0.25 × 2.125
Length of the pipe = 0.53125 m
Length of the pipe = 53.125 cm
Answer:
when he uses more force to hit the drum then its makes a louder sound so the more force you hit the drum with then the louder it is.