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velikii [3]
3 years ago
7

In the inverse variation function, what happens to the output when the function's input value is divided by 5?

Mathematics
2 answers:
bagirrra123 [75]3 years ago
5 0
The output is multiplied by 5....................

Zolol [24]3 years ago
5 0
<h2>Answer: </h2>

The output value will be multiplied by 5.

<u>Step-by-step explanation:</u>

The equation for inverse variation is given by :-

k=yx

OR

y=\frac{k}{x}, where x is representing input values and y representing output values.

If input value is divided by 5 (i.e.x_1=\frac{x}{5}), then the above equation will be

y_1=\frac{k}{\frac{x}{5}}\\\\\Rightarrow y_1=5(\frac{k}{x})\\\\\Rightarrow y_1=5y

Thus, when the function's input value is divided by 5 then the output value will be multiplied by 5.

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Answer:

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We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

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P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

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you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

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you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

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