Question

An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 N/m.
What is the force applied to the scale by the car?

_____N

Answer 1

Using F = Ke
F = 39200×(25÷100) = 39200×0.25
F= 9800N

Answer 2

Answer:

Force, F = 9800 N

Explanation:

It is given that,

The spring constant for the industrial scale at the junkyard is, k = 39,200 N/m

The compression in the spring, x = 25 cm = 0.25 m

To find,

The force applied to the scale by the car.

Solution,

The Hooke's law gives the relation between the force and the compression in the spring. Its expression is given by :

$F=-kx$

$F=39200\times 0.25$

F = 9800 N

So, the force applied to the scale by the car is 9800 N.