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2 years ago

If we replace y with x2cos x and solve for y', we can conclude that the derivative is

Mathematics

1 answer:

marusya05 [52]2 years ago

5 0

Y = x^2 cos x

y' = x^2 * -sin x + cos x * 2x

= 2x cos x - x^2 sin x

= x ( 2 cos x - x sin x)

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Dafna1 [17]

Answer:

$\huge\boxed{ \red{ \boxed{ \tt{ \frac{ {y}^{2} }{ {10}^{2} } - \frac{ {x}^{2} }{ {12}^{2} } = 1}}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

conic sections
PEMDAS

<h3>tips and formulas:</h3>

$\sf hyperbola \:equation : \\ \sf \frac{ {x}^{2} }{ {a}^{2} } - \frac{ {y}^{2} }{ {b}^{2} } = 1$
vertices of hyperbola:(±a,0) and (0,±b) if reversed
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<h3>given:</h3>

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<h3>let's solve:</h3>

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according to the question

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let's create the equation:

$\sf substitute \: the \: value \: of \: a \: and \: b : \\ \sf \frac{ {y}^{2} }{ {10}^{2} } - \frac{ {x}^{2} }{ {12}^{2} } = 1$

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marusya05 [52]

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