Answer:
Try solving 6(n-5)-2.
Step-by-step explanation:
I believe this can be set up as 6(n-5)-2. The difference of a number and five can be represented by n-5. If this needs to be multiplied by 6 (hence 6 times), it would become 6(n-5). Two less than that is represented by -2. Thus, two less than six times the difference of a number and five is 6(n-5) -2, which, when n=9 is plugged in, looks like 6(9-5) -2. Follow PEMDAS from there.
9 hundreds=900 9 thousands=9,000
Assuming that she goes every day of the month and one month has 30days:
Let the fee per class of Fit Fast be x.
Let <span>the fee per class of Stepping Up be y.
Let </span><span>the fee per month of Stepping Up be z.
Fit fast fee(if she does for this choice) - 30x
Stepping up fee</span><span>(if she does for this choice) - 30y + z
Im not sure of what the costs are as you did not state but here it is...hope this helps:)</span>
Answer:
-2
Step-by-step explanation:
x-8=-10
x=-10+8
x=-2
