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3 years ago

PLEASE HELP MEEEEE!!!!

Mathematics

1 answer:

defon3 years ago

8 0

Answer:

Step-by-step explanation:

The leading coefficient is the coefficient with a variable with the greatest exponent.The exponent is the number you would say "the power to". What I mean is let's say you have this number: $3^{2}$ . The exponent would be 2 in this equation because it's saying what power 3 is too. Therefore, 5 is the leading coefficient.

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If there are 12 eggs in a carton, how many are in 5 cartons?

Elan Coil [88]

Answer:

Step-by-step explanation:

12x5 is equal to 60

8 0

2 years ago

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the equation of line cd is y = 3x − 3. write an equation of a line perpendicular to line cd in slope-intercept form that contain

liberstina [14]

Answer:

The required equation is $y=-\frac{1}{3}x+2$ .

Step-by-step explanation:

The equation of line cd is

$y=3x-3$

Slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

Slope of line cd is 3.

The product of slopes of two perpendicular lines is -1.

$m_1\times m_2=-1$

$3\times m_2=-1$

$m_2=-\frac{1}{3}$

Therefore slope of perpendicular line is $-\frac{1}{3}$ .

Point slope form of a line is

$y-y_1=m(x-x_1)$

Slope of perpendicular line is $-\frac{1}{3}$ and line passing through the point (3,1).

$y-1=-\frac{1}{3}(x-3)$

$y=-\frac{1}{3}x+1+1$

$y=-\frac{1}{3}x+2$

Therefore the required equation is $y=-\frac{1}{3}x+2$ .

4 0

3 years ago

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What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success p? C

charle [14.2K]

Answer:

$(D)E[ X ] =np.$

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success p,

$f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq x\leq n$

$E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}$

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

$E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}$

Now,

$x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)$