Answer: A (x,y) is your original. Your answer after would be A' (-x,-y) you would change the sign. If its negative it becomes positive, and if it'd positive it becomes negative.
Answer:
A
The test statistics is ![t = -1.7](https://tex.z-dn.net/?f=t%20%20%3D%20-1.7)
B
The Null and Alternative hypothesis are
and ![H_a : \mu \ne 47.2](https://tex.z-dn.net/?f=H_a%20%3A%20%20%5Cmu%20%5Cne%20%2047.2)
Step-by-step explanation:
From the question we are told that
The population mean is ![\mu = 47.2 miles/gallon(MPG)](https://tex.z-dn.net/?f=%5Cmu%20%20%3D%20%2047.2%20miles%2Fgallon%28MPG%29)
The sample size is ![n = 250 \ van](https://tex.z-dn.net/?f=n%20%3D%20%20250%20%5C%20van)
The sample mean is ![\= x = 47.0](https://tex.z-dn.net/?f=%5C%3D%20x%20%20%3D%20%2047.0)
The sample standard deviation is ![\sigma = 1.9](https://tex.z-dn.net/?f=%5Csigma%20%20%3D%20%201.9)
The level of significance is ![\alpha = 0.02](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%200.02)
Given that the value which the manufacturer gave the automobile is 47.2 and it is believed that this is not correct, then
The Null Hypothesis is
![H_o : \mu = 47.2](https://tex.z-dn.net/?f=H_o%20%20%3A%20%20%5Cmu%20%3D%2047.2)
The alternative Hypothesis is
![H_a : \mu \ne 47.2](https://tex.z-dn.net/?f=H_a%20%3A%20%20%5Cmu%20%5Cne%20%2047.2)
The test statistics can be mathematically evaluated as
![t = \frac{\= x- \mu}{\frac{\sigma }{\sqrt{n} } }](https://tex.z-dn.net/?f=t%20%20%3D%20%20%5Cfrac%7B%5C%3D%20x-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%20%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D)
substituting values
![t = \frac{\= 47- 47.2}{\frac{1.9 }{\sqrt{250} } }](https://tex.z-dn.net/?f=t%20%20%3D%20%20%5Cfrac%7B%5C%3D%2047-%2047.2%7D%7B%5Cfrac%7B1.9%20%7D%7B%5Csqrt%7B250%7D%20%7D%20%7D)
![t = -1.7](https://tex.z-dn.net/?f=t%20%20%3D%20-1.7)
Answer:
Mr. Chan's total account receivable is of $212,500.
Step-by-step explanation:
$85,000 this month this represents 40% of our receivables
This means that 85000 is 40% = 0.4 of the receivables, which is x.
What is mr. Chan's total account receivable?
We have to find x
![0.4x = 85000](https://tex.z-dn.net/?f=0.4x%20%3D%2085000)
![x = \frac{85000}{0.4}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B85000%7D%7B0.4%7D)
![x = 212500](https://tex.z-dn.net/?f=x%20%3D%20212500)
Mr. Chan's total account receivable is of $212,500.
Easy the 3 is in the ten thousands place