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valentina_108 [34]
3 years ago
15

Catron evaluates the expression (negative 9) (2 and two-fifths) using the steps below.

Mathematics
2 answers:
Vlad [161]3 years ago
6 0

Answer:

Catron's error is

"She did not follow order of operations"

Step-by-step explanation:

Catron evaluates the expression (negative 9) (2 and two-fifths)

That expression can be written as below

(-9)(2\frac{2}{5})

Catron's error is

"She did not follow order of operations"

The corrected steps are

Step1: Given expression is (-9)(2\frac{2}{5})

Step2: Convert mixed fraction into improper fraction

(-9)(2\frac{2}{5})=(-9)(\frac{12}{5})

Step3: Multiplying the terms

(-9)(2\frac{2}{5})=-7\frac{-108}{5}

Therefore solution (-9)(2\frac{2}{5})=-7\frac{-108}{5}

GrogVix [38]3 years ago
4 0

Answer:

Catron'error is that She incorrectly broke up 2 and two-fifths.

Step-by-step explanation:

Following Catron steps we have:

-9(2 + \frac{2}{5} )\\-9(-2) + (-9)(\frac{2}{5} )\\-18 + (-9)(\frac{2}{5} )\\-27(\frac{2}{5} )\\-\frac{54}{5}  = - 10\frac{4}{5}

Catron did not represent the problem correctly.

The correct step is:

-9(2 \frac{2}{5} )\\-9(\frac{10 + 2}{5} )\\-9(\frac{12}{5} )\\-(\frac{108}{5} )\\= - 21\frac{3}{5}

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3 0
3 years ago
Q(a+1) - 2q(a) if q(x) = x²+3x+4​
siniylev [52]

q(x) =  {x}^{2} + 3x + 4

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

q(a) =  {a}^{2} + 3a + 4

Multiply sides by -2 :

- 2q(a) =  - 2( {a}^{2} + 3a + 4)

- 2q(a) =  - 2 {a}^{2} - 6a - 8

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

q(a + 1) =  ({a + 1})^{2} + 3(a + 1) + 4 \\

q(a + 1) =  {a}^{2} + 2a + 1 + 3a + 3 + 4 \\

q(a + 1) =  {a}^{2} + 5a + 8

_________________________________

Step (3)

q(a + 1) - 2q(a) =

{a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 =  \\

-  {a}^{2} - a  =  - a(a + 1)

And we're done.

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