This will be a 4th degree polynomial. Our root of x = 7 in factorization form is (x-7). Our root of x = -11 in factorization form is (x+11) and the last one is a complex number. According to the conjugate root theorem, if we have 2+8i, we also HAVE to have 2-8i. In factorization form that first one is (x-(2+8i)) which simplifies to (x-2-8i). Its conjugate in factorization form is (x-2+8i). Now we will FOIL all that out. Let's start with the (x-2-8i)(x-2+8i). That multiplies out to . We have to combine like terms here to shorten that a bit. . i^2 is equal to -1, and -1(64) = -64. Now we have . That is . Now let's FOIL in another factorization. . That comes out to . One more term to go! . That, finally, is .