All categories

2 years ago

Write a balanced chemical equation, including states of matter, for the combustion of gaseous benzene, c6h6.

1 answer:

4 0

Almost all hydrocarbon 'burn' reactions involve oxygen; it's by far the most reactive substance in air.

<span>Hydrocarbon combustions always involve </span>
<span>[some hydrocarbon] + oxygen --> carbon dioxide + steam. </span>

C6H6(l) + O2 (g)--> CO2 (g)+ H2O (g)

<span>Balance carbon, six on each side: </span>
C6H6(l) + O2 (g)--> 6CO2 (g)+ H2O (g)

<span>Balance hydrogen, six on each side: </span>
C6H6(l) + O2 (g)--> 6CO2(g) + 3H2O (g)

<span>Now, we have fifteen oxygens on the right and O2 on the left. </span>
<span>Two ways to deal with that. We can use a fraction: </span>
C6H6 (l)+ (15/2)O2 (g)--> 6CO2 (g)+ 3H2O (g)

<span>Or, if you prefer to have whole number coefficients, double everything </span>
<span>to get rid of the fraction: </span>
2C6H6 (l)+ 15O2 (g)--> 12CO2 (g)+ 6H2O (g)

<span>With the SATP states thrown in... </span>
C6H6(l) + (15/2)O2(g) --> 6CO2(g) + 3H2O(g)

You might be interested in

How do you balance this Chemical Equation? <br>C5H12O + O2 = CO2 + H2O

ICE Princess25 [194]

Answer:

The chemical equation by putting, a 2 on C₅H₁₂O, 15 on O₂, 10 on CO₂ , and 12 on H₂O in the equation;

2C₅H₁₂O + 15O₂ → 10CO₂ + 12H₂O

Explanation:

Chemical equations are balanced by putting coefficients on the reactants and products to ensure the total number of atoms on the left side equal to those on the right side.
Balancing chemical equations is done to make chemical equations obey the law of conservation of mass.
According to the law of conservation of mass, the mass of the reactants should always be equal to the mass of products.
This is done by balancing chemical equations to ensure the total number of atoms on the left side is equal to that on the right side.

Therefore, the balanced equation is;

2C₅H₁₂O + 15O₂ → 10CO₂ + 12H₂O

3 0

2 years ago

5. What concentration of acid must be added to change the pH of 1 mM phosphate buffer from 7.4 to 7.3 (pKas of the phosphate buf

mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and $pK_{a}$ is as follows.

pH = $pK_{a} + log \frac{base}{acid}$

where, pH = 7.4 and $pK_{a}$ = 7.21

As here, we can use the $pK_{a}$ nearest to the desired pH.

So, 7.4 = 7.21 + $log \frac{base}{acid}$

0.19 = $log \frac{base}{acid}$

$\frac{base}{acid}$ = 1.55

1 mM phosphate buffer means $[HPO_{4}]$ + $[H_{2}PO_{4}]$ = 1 mM

Therefore, the two equations will be as follows.

$\frac{HPO_{4}}{H_{2}PO_{4}}$ = 1.55 ............. (1)

$[HPO_{4}]$ + $[H_{2}PO_{4}]$ = 1 mM ........... (2)

Now, putting the value of $[HPO_{4}]$ from equation (1) into equation (2) as follows.

1.55 $[H_{2}PO_{4}] + [tex][H_{2}PO_{4}]$ = 1 mM

2.55 $[H_{2}PO_{4}]$ = 1 mM

$[H_{2}PO_{4}]$ = 0.392 mM

Putting the value of $[H_{2}PO_{4}]$ in equation (1) we get the following.

0.392 mM + $[HPO_{4}]$ = 1 mM

$[HPO_{4}]$ = (1 - 0.392) mM

$[HPO_{4}]$ = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0

2 years ago

Nicotine is 74.1% carbon, 8.6% hydrogen, and 17.3% nitrogen by mass. What is its molecular formula if its molar mass is 162.26 g

WINSTONCH [101]

first we need to find the empirical formula of nicotine

empirical formula is the simplest ratio of whole numbers of elements making up a compound

the percentage compositions for each element has been given. So we can calculate for 100 g of the compound.

masses of elements and the number of moles

C - 74.1 g - 74.1 g/12 g/mol = 6.17 mol

H - 8.6 g - 8.6 g / 1 g/mol = 8.6 mol

N - 17.3 g - 17.3 g / 14 g/mol = 1.23

divide all by the least number of moles

C - 6.17 / 1.23 = 5.01

H - 8.6 / 1.23 = 6.99

N - 1.23 / 1.23 = 1.00

when the atoms are rounded off to the nearest whole numbers

C - 5

H - 7

N - 1

empirical formula is C₅H₇N

we have to find what the mass of 1 empirical unit is

mass - 5 x 12 g/mol + 7 x 1 g/mol + 14 g/mol = 81 g

molecular mass is 162.26 g/mol

we have to find how many empirical units make up 1 molecule

number of empirical units = molecular mass / mass of 1 empirical unit

= 162.26 g/mol / 81 g = 2.00

there are 2 empirical units

molecular formula is - 2 (C₅H₇N)

molecular formula - C₁₀H₁₄N₂

4 0

3 years ago

Read 2 more answers

Develop a message for the owners of cars in villages explaining why the vehicles should be kept well even if they are spoiled, w

Lera25 [3.4K]

<h2>Answer:</h2>

<h3>#Carry On Learning</h3>

<h2>Explanation:</h2>

3 0

2 years ago

What is the speed of a wave that has a frequency of 220 Hz and a wavelength

alekssr [168]

Answer:

12d

Explanation:

7 0

2 years ago