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Sidana [21]
2 years ago
10

Briefly describe bohr's model postulates and its limitations.​

Chemistry
1 answer:
ch4aika [34]2 years ago
8 0

<u>Answer:</u>

<u>Bohr's Model postulates-</u>

I postulate - The electrons in an atom orbit around the nucleus in definite circular paths called orbits or shells.

II Postulate - Each shell or orbit represents a specific amount of energy.

III Postulate - By emitting or absorbing energy, an electron may shift from one stationary energy orbit to another.

<u>Three main Limitations -</u>

1- It adjusts to the hydrogen atom's spectrum but not to the spectra of other atoms.

2 - In the definition of the electron as a tiny particle that spins around the atomic nucleus, the wave properties of the electron are not described.

3- Bohr is unable to understand why classical electromagnetism is inapplicable to his model. That is why, when electrons are in a stationary orbit, they do not emit electromagnetic radiation.

Explanation:

<u>About Bohr's postulates-</u>

1 - The electron spins in circling circles around the nucleus, emitting no energy. The orbital angular momentum is constant in these orbits.

Only certain radii of orbits, corresponding to certain given energy levels, are required for electrons in an atom.

2- Not every orbit is possible. However, whenever an electron is in a legal orbit, it is in a state of unique and constant energy and does not emit energy (stationary energy orbit).

<u>For example -</u> The energies allowed for electrons in the hydrogen atom are given by the following equation: The Rydberg constant for the hydrogen atom is -2.8\times10^-^1^8 in this equation, and n = quantum number will range from 1 to ∞. For each of the values of n, the electron energies of a hydrogen atom produced by the above equation are negative. As n rises, the energy becomes less negative and thus rises.

3- By emitting or absorbing energy, an electron may shift from one stationary energy orbit to another.

The energy difference between the two states would be equal to the energy released or consumed. This energy E is in the form of a photon, and it can be measured using the following formula:

    E=hv

E is the energy (absorbed or emitted) in this equation, and h is the Planck constant (its value is 6.63\times10^-^3^4 Js) and v denotes the frequency of light, which is calculated in 1/ s.

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A dehydration reaction starting with 3.8 g cyclohexanol produces 2.6 g cyclohexene. Calculate the theoretical yield for this rea
diamong [38]

Answer:

Theoretical yield of C6H10 = 3.2 g.

Explanation:

Defining Theoretical yield as the quantity of product obtained from the complete conversion of the limiting reactant in a chemical reaction. It can be expressed as grams or moles.

Equation of the reaction

C6H11OH --> C6H10 + H2O

Moles of C6H11OH:

Molar mass of C6H110H = (12*6) + (1*12) + 16

= 100 g/mol

Mass of C6H10 = 3.8 g

number of moles = mass/molar mass

=3.8/100

= 0.038 mol.

Using stoichoimetry, 1 moles of C6H110H was dehydrated to form 1 mole of C6H10 and 1 mole of water.

Therefore, 0.038 moles of C6H10 was produced.

Mass of C6H10 = molar mass * number of moles

Molar mass of C6H10 = (12*6) + (1*10)

= 82 g/mol.

Mass = 82 * 0.038

= 3.116 g of C6H10.

Theoretical yield of C6H10 = 3.2 g

4 0
3 years ago
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Answer:

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Explanation:

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If you burn 48.6 g of hydrogen and produce 434 g of water, how much oxygen reacted?
GarryVolchara [31]

Answer:

            385.69 g of O₂

Solution:

The Balance Chemical equation for said reaction is as follow;

                                       2 H₂  +  O₂    →   2 H₂O

According to Equation,

        4.032 g ( 2 mol) H₂ reacts to produce  =  36.03 g (2 mol) of H₂O

So,

        48.6 g H₂ on reaction will produce  =  X g of H₂O

Solving for X,

                     X =  (48.6 g × 36.03 g) ÷ 4.032 g

                     X  =  434.29 g of H₂O

It means that the H₂ provided is in Excess. Therefore, the yield of product (H₂O) is being controlled by O₂ (Limiting Reagent).

So, According to Equation,

                    36.03 g (2 mol) H₂O is produced by  =  31.998 g (1 mol) of O₂

So,

                434.29 g of H₂O will be produced by  =  X g of O₂

Solving for X,

                     X =  (434.29 g × 31.998 g) ÷ 36.03 g

                    X  =  385.69 g of O₂

8 0
2 years ago
The silver nitrate in 20.00 mL of a certain solution was allowed to react with sodium chloride according to the following equati
valentinak56 [21]

Answer:

The answer to your question is: 0.1 M

Explanation:

data

Volume of AgNO3 = 20.00 ml

                   1000 ml --------------  1 l

                       20 ml --------------- x              

          x = 20x 1 /1000 = 0.02

AgCl = 0.2867 g

MW of AgCl = 35.45 + 107.9 = 143.35 g

                       143.35 g -------------- 1 mol

                       0.2867 g -------------  x

  x = 0.2867 x 1 / 143.35 = 0.002 moles of AgCl

   From the balance reaction we see that the proportion of AgNO3 to AgCl is 1:1, then

           1 mol of AgNO3 -------------------- 1 mol of AgCL

                 x                   ---------------------  0.002 moles of AgCl

 x = 0.002 moles of AgNO3

   This moles of AgNO3 are in 20 ml or 0.02 liters

So, Molarity = # moles/liter

      Molarity = 0.002 moles/ 0.02 = 0.1 M

4 0
2 years ago
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