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artcher [175]
3 years ago
9

(a) (1)

Chemistry
1 answer:
Elis [28]3 years ago
8 0

Explanation:

The ionization energy of an atom is the amount of energy that is required to remove an electron from a mole of atoms in the gas phase:

M(g)  ®  M+(g)  +  e-

It is possible to remove more electrons from most elements, so this quantity is more precisely known as the first ionization energy, the energy to go from neutral atoms to cations with a 1+ charge.  The second ionization energy is the energy that is required to remove a second electron, to form 2+ cations from 1+ cations:

M+(g)  ®  M2+(g)  +  e-

The third ionization energy is the energy required to form 3+ cations:

M2+(g)  ®  M3+(g)  +  e-

and so on.  Ionization energies are always positive numbers, because energy must be supplied (an endothermic energy change) to separate electrons from atoms.  The second ionization energy is always larger than the first ionization energy, because it requires even more energy to remove an electron from a cation than it is from a neutral atom.

The first ionization energy varies in a predictable way across the periodic table.  The ionization energy decreases from top to bottom in groups, and increases from left to right across a period.  Thus, helium has the largest first ionization energy, while francium has one of the lowest.

From top to bottom in a group, orbitals corresponding to higher values of the principal quantum number (n) are being added, which are on average further away from the nucleus.  Since the outermost electrons are further away, they are less strongly attracted by the nucleus, and are easier to remove, corresponding to a lower value for the first ionization energy.From left to right across a period, more protons are being added to the nucleus, but the number of electrons in the inner, lower-energy shells remains the same.  The valence electrons feel a higher effective nuclear charge — the sum of the charges on the protons in the nucleus and the charges on the inner, core electrons.  The valence electrons are therefore held more tightly, the atom decreases in size (see atomic radius), and it becomes increasingly difficult to remove them, corresponding to a higher value for the first ionization energy.

 

The following charts illustrate the general trends in the first ionization energy:

Dunno kung tama beng pero trysorry kung mali

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Which group (give the number) is characterized by 5 valence electrons in the configuration<br> s²p3?
Ivahew [28]
<h3>Answer:</h3>

Group 5A

<h3>Explanation:</h3>
  • Elements in the periodic table are arranged into columns known as groups and rows known as periods.
  • Elements in the same group share similar chemical properties.
  • For example, elements in group 5A have five valence electrons with the most high energy level with a configuration of s²p³.
  • Elements in group 5A include nitrogen and phosphorus among others.
5 0
4 years ago
OFFERING 50 POINTS
defon

a. cesium and sulfur would be an ionic bond (metal + non-metal)

b. chlorine and bromine would be a covalent bond (non-metal+ non-metal)

c. magnesium and fluorine would be ionic again (metal + non-metal)

d. silver and mercury would be a metallic bond I'm pretty sure at least (metal+metal)

7 0
3 years ago
Which solution has the higher boiling point: 42.0 g c2h6o2 in 0.500 kg of h2o or 35.0 g nacl in 0.500 kg of h2o?
Lelechka [254]

Answer:

  • The NaCl solution will have higher boiling point.

Explanation:

  • C2H6O2 is a molecular substance. Meaning that when it dissolves it will remain this way:

                                  C2H6O2 ---------> C6H12O6 (aq)  

  • Sodiumchloride (NaCl) is an ionic substance. Meaning that when it dissolves, it will create ions:

                                   NaCl(s)-------> Na+(aq) + Cl- (aq)

Conclusion:

  • NaCl is an ionic compound and C2H6O2 is a molecular compound. Ionic compounds have higher boiling points than molecular compounds. Therefore, NaCl will have the higher boiling point.
6 0
3 years ago
A 0.100 M solution of chloroacetic acid 1ClCH2COOH2 is 11.0% ionized. Using this information, calculate 3ClCH2COO-4, 3H 4, 3ClCH
bearhunter [10]

Answer:

[CICH2COOH] = 0.089 M

[CICH2COO-] = 0.011 M

[H+] = 0.011 M

Ka = 1.36 x 10^-3

Explanation:

The reaction

CICH2COOH  ⇄ H+ (aq) + CICH2COO- (aq)

The initial concentration of CICH2COOH is 0.10 M , chloroacetic acid is 11.0% ionized.

let us calculate Ka

First , find change in concentration

since , 11% ionized

change in concentration = 0.10 X 11% = 0.011 M

Initial Concentration of CICH2COOH = 0.10 M

change in concentration of CICH2COOH = - 0.011 M

Equilibrium Concentration of CICH2COOH = 0.10 M - 0.011 M = 0.089 m

Initial Concentration of CICH2COO- = 0 M

change in concentration of CICH2COO- = + 0.011 M

Equilibrium Concentration of CICH2COO- = 0.011 M

Initial Concentration of H+ = 0 M

change in concentration of H+ = + 0.011 M

Equilibrium Concentration of H+ = 0.011 M

Therefore,

[CICH2COOH] = 0.089 M

[CICH2COO-] = 0.011 M

[H+] = 0.011 M

Ka = [H+][CICH2COO-] /[CICH2COOH]

Ka = (0.011 * 0.011) / (0.089)

Ka = 1.36 x 10^-3

6 0
3 years ago
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aalyn [17]

Answer:

gases are compressible and liquids arent

Explanation:

molecules of liquids have a very little space between them...but gas molecules have a larger space between them...so we can easily compress them...when we compresse them enough...at right temperature...even whole atmosphere turn in to liquid....

3 0
3 years ago
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