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Studentka2010 [4]
4 years ago
9

What are 3 signs that a chemical change (chemical reaction) has taken or is taking place?

Chemistry
1 answer:
kotykmax [81]4 years ago
6 0
Heat has been released or lost. Odor may be present. Absence of a substance may be converted to something else.
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A sample of gas occupies 3.00 L with 5.00 moles present. What would
pantera1 [17]

3/5 times 5/3x = 8*3/5. X=24/5 simplified would be x= 4.8 L.

5 0
3 years ago
What happens when an ecosystem reaches the maximum number of individuals it can support
tangare [24]

Answer:

A collapse of the population is rotting, food is not enough and livelihoods have become unfeasible to decrease the number of individuals again.

Another way is to generate mutations to generate a species more vulnerable to decreasing numbers.

In this way the overpopulation is controlled.

Explanation:

In ecosystems, if an increased population breaks the balance of this and begins a new constant adaptation of the extinction of some and overpopulation of others, which may be some chains break or remain unstable.

6 0
3 years ago
Why is the periodic table such a brilliant piece of work? Explain and give two reasons.​
Aleksandr-060686 [28]

Answer:

Because it keeps track of all the elements

6 0
3 years ago
If you try to place the compound on the pan over the flame, what could possibly happen? Explain your answer. [2 marks] anyone pl
Scilla [17]

Answer:

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8 0
3 years ago
Someone please do this!!!
Lilit [14]

Answer:

1) Fe = 69.9%

O = 31.1%

2) H = 5.19%

O = 16.5%

N = 28.9%

C = 49.5%

Explanation:

One easy way to do percent compositions is to assume you have 100g of a substance.

1) Lets say we have 100g of Fe2O3.

The total molar mass would be:

= 55.845*2+15.999*3 = 159.687

The molar mass of the Fe2 alone is:

=55.845*2 = 111.69

Thus, the grams of Fe2(out of a 100) could be calculated by multiplying 100g * the molar mass ratio of Fe2 to the whole:

= 100g *\frac{111.69}{159.687} = 69.9431

Which is approximately 69.9%.

We can find the amount of O3 by simply subtracting, as the rest of the compound is made of O3. Thus, the % composition of O3 is 31.1%

You can then do this same process to the next question, getting us the following:

H = 5.19%

O = 16.5%

N = 28.9%

C = 49.5%

4 0
3 years ago
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