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3 years ago

How many neutrons does an element have if its atomic number is 41 and its mass number is 170?

Chemistry

1 answer:

BARSIC [14]3 years ago

7 0

atomic number = protons.

protons+neutrons=atomic mass.

170 (mass) - 41 (proton/number) = 129

that should be ur answer. I hope this helps!

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A quantity of an ideal gas is compressed to half its initial volume. the process may be adiabatic, isothermal or isobaric. the g

JulsSmile [24]

the greatest amount of work is required if the process is adiabatic.The correct option is adiabatic.

The process in which heat is constant is called adiabatic process.

The The process in which temperature is constant is called isothermal process.

The process in which pressure is constant is called isobaric process.

The P-V diagram for adiabatic , isothermal and isobaric process is given below.

Work done in process = area encloses by P-V diagram axis . Since area under the curve is maximum for adiabatic process which is shown in the above diagram. So, work done by the gas will be maximum for adiabatic process.

learn more about adiabatic process.

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8 months ago

1 mole of any gas is equivalent to?

iragen [17]

Answer:

22.4 L at standard temperature and pressure.

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2 years ago

How many moles are in 12.9 grams of Fe?

amid [387]

Answer:

0.1677 is the answer

Explanation:

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2 years ago

Read 2 more answers

A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

$-w=\frac{dm}{dt}$

w is the mass flow

m is the mass of salt

$-v*C=\frac{dm}{dt}$

v is the volume flow

C is the concentration

$C=\frac{m}{V+(6-3)*L/min*t}$

$-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}$

$-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}$

$-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)$

$-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)$

$m=90kg*[2000L/(2000L+3*L/min*t)]$

a) Initially: t=0

$m=90kg*[2000L/(2000L+3*L/min*0)]=90kg$

b) t=210 min (3.5 hr)

$m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg$

c) If time trends to infinity the division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

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3 years ago

How many atoms of each element are in one molecule of 2-heptanone?

Alex17521 [72]

A chemical structure of a molecule includes the arrangement of atoms and the chemical bonds that hold the atoms together. The 2-HEPTANONE molecule contains a total of 21 bond(s) There are 7 non-H bond(s), 1 multiple bond(s), 4 rotatable bond(s), 1 double bond(s) and 1 ketone(s) (aliphatic).

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2 years ago