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r-ruslan [8.4K]
3 years ago
7

Water expands when heated. Suppose a beaker of water is heated from 10℃ to 90℃. Does the pressure at the bottom of the beaker in

crease, decrease, or stay the same? Explain.
Chemistry
1 answer:
mamaluj [8]3 years ago
8 0
<h2>The Pressure Increases </h2>

Explanation:

  • When the water is heated from 10℃ to 90℃ the pressure at the bottom of the beaker will also increase.
  • For a closed system with liquid contents that is water, the pressure will always increase with a rise in temperature.

       By using the formula;  

      \frac{P_1V_1}{T_1}= \frac{ P_2V_2}{T_2}

       where,

      V1 & V2 are the volumes at the initial level and final level, both the volumes are the same(ignoring pressure distention), T1 & T2 are the temperatures and   P1 & P2 are the pressures.

      Therefore, we get the pressure excluding the volumes as -

     P_2 =\frac{T_2P_1}{T_1}

  • Hence, according to the above explanation, if the temperature of the water increases then the pressure at the bottom of the beaker is also increased.
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This problem is providing us with the mass equivalent to one troy ounce. Thus, the troy ounces of gold in one short ton of average Nevada ore is required and found to be the 0.103 otz according to the following dimensional analysis.

<h3>Dimensional analysis</h3>

In chemistry, a raft of problems do not always provide an equation in order to be solved yet dimensional analysis can be applied, so as to obtain the desired amount in the required units.

Thus, since this problem asks for try ounces in an average Nevada ore,  which has 3.2 grams of gold per short ton of ore, one can solve the following setup in order to obtain the required answer in otz:

\frac{3.2gAu}{1short-ton}*1short-ton*\frac{1otz}{31.1g} \\

Where the short tons are cancelled out as well as the grams, in order to obtain:

0.103 otz

Learn more about dimensional analysis: brainly.com/question/10874167

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