1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
r-ruslan [8.4K]
3 years ago
7

Water expands when heated. Suppose a beaker of water is heated from 10℃ to 90℃. Does the pressure at the bottom of the beaker in

crease, decrease, or stay the same? Explain.
Chemistry
1 answer:
mamaluj [8]3 years ago
8 0
<h2>The Pressure Increases </h2>

Explanation:

  • When the water is heated from 10℃ to 90℃ the pressure at the bottom of the beaker will also increase.
  • For a closed system with liquid contents that is water, the pressure will always increase with a rise in temperature.

       By using the formula;  

      \frac{P_1V_1}{T_1}= \frac{ P_2V_2}{T_2}

       where,

      V1 & V2 are the volumes at the initial level and final level, both the volumes are the same(ignoring pressure distention), T1 & T2 are the temperatures and   P1 & P2 are the pressures.

      Therefore, we get the pressure excluding the volumes as -

     P_2 =\frac{T_2P_1}{T_1}

  • Hence, according to the above explanation, if the temperature of the water increases then the pressure at the bottom of the beaker is also increased.
You might be interested in
How many grams of H2O are in 34.2 grams of NAOH<br> Need ASAP
Brrunno [24]

Answer:

15.438g H2O

Explanation:

First you need to find the reaction equation:

2H2O+2Na=2NaOH + H2

Hydrogen is a diatomic molecule so it will have a subscript of 2 on the right hand side. From there we can balance the reaction.    

Then we can use stoichiometry:

34.2g NaOH * (1 mol NaOH/39.908g NaOH) * (2 mol H2O/2 mol NaOH) * (18.015g H2O/1 mol H20) = 15.438g H2O

It is important that when you use stoichiometry that all your units cancel out until you only have the unit you want.

3 0
2 years ago
URGENT HELP PLEASE balance equation !20 points!
yKpoI14uk [10]
Au^2S^3+ 3H^2 = 2Au + 3H^2S
5 0
3 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

brainly.com/question/20305871

#SPJ1

5 0
1 year ago
The gases that make up Earth’s atmosphere are commonly referred to as air. Air consists of major gases and trace gases. What is
Snezhnost [94]

Air is a mixture, Its constituens can be seperated

8 0
2 years ago
The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

4 0
2 years ago
Other questions:
  • 3. The following equation represents the reaction between N,
    8·1 answer
  • write a statement that makes a claim about arrangements of electrons and properties within a family of elements
    10·1 answer
  • The partial pressure of carbon dioxide in systemic arterial blood is __________. the partial pressure of carbon dioxide in syste
    15·1 answer
  • Which of these four elements is the most reactive metal?​
    6·2 answers
  • What is the mass of 2.56 × 10–4 moles of Fe2O3? : 6.23 × 105 159.6 g 1.60 × 0–6 g 4.09 × 10–2 g
    9·1 answer
  • Convert to grams<br> 0.100 moles of Co2
    12·1 answer
  • Please explain the difference between reactants and products in a chemical reaction.
    11·1 answer
  • I exercise
    5·1 answer
  • Why is space cold ???
    10·1 answer
  • How many atoms are present in 2g of hydrogen gas​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!