What does water transmit

pychu [463]

Answer:

The slope of the line is $-\frac{10}{7}$ .

Explanation:

The slope of the line ( $m$ ) is the change in dependent variable ( $y$ ) divided by the change in independent variable ( $x$ ):

$m = \frac{y_{f}-y_{o}}{x_{f}-x_{o}}$ (1)

If we know that $(x_{o}, y_{o}) = (0, 2)$ and $(x_{f}, y_{f}) = (1.4, 0)$ , then the slope of the line is:

$m = \frac{0-2}{1.4-0}$

$m = -\frac{10}{7}$

The slope of the line is $-\frac{10}{7}$ .

3 0

2 years ago

PLEASE HELPPPP IM GIVING THE TEST RN

Tom [10]

Answer:

answer is c

Explanation:

single replacement

6 0

2 years ago

My swimming pool is rectangular (16 feet by 34 feet) and has a depth of 6 feet. Lets imagine that my pool water is full to the t

Reil [10]

Answer:

Number of moles of photons required = 5.04 × 10⁴ moles

Explanation:

The energy of a photon can be calculated from Planck's equation E = hc/λ

Where h = 6.63 × 10-³⁴ Js and c, the velocity of light = 3.0 × 10⁸ m/s

Energy of one mole of photons = N₀ × hc/λ

wavelength of photon, λ = 520 nm = 5.20 × 10-⁷ m

Energy of one mole of photons = 6.02 × 10²³ × 6.63 × 10−³⁴ × 3 × 10⁸/5.20 × 10-⁷

Energy of one mole of photons = 2.30 × 10⁵ J/mol

Energy required to raise the temperature of a given mass of a substance, E = mcΔT

Where m is mass of substance, c is specific heat capacity, ΔT is temperature difference

Mass ofnwternin the pool = volume × density

Volume of water = Volume of swimming pool

Volume of water = 16 × 34 × 6 ft³ = 3264 ft³

1 ft³ = 28316.8 cm³; 3264 ft³ = 28316.8 × 3264 = 92426035.2 cm³

Density of water = 1 g/cm³

Mass of water = 92426035.2 cm³ × 1 g/cm³ = 92426035.2g

ΔT = 80°C - 50°C = 30°C, c = 4.18 J/g/K

Energy required to raise 92426035.2 g water by 30° C = 92426035.2 × 4.18 × 30

Energy required = 1.16 × 10¹⁰ J

Hence, number of moles of photons required = 1.16 × 10¹⁰ J/2.30 × 10⁵ J/mol

Number of moles of photons required = 5.04 × 10⁴ moles

5 0

3 years ago

Draw the structure for 1-nitrobutane, making sure to add all non-zero formal charges.

TiliK225 [7]

The molecular structure of 1-nitrobutane is $C_{4} H_{9} NO_{2}$ . The structure of 1-nitrobutane is shown below.

An atom's formal charge would be determined by the covalent model of chemical bonding, which assumes that almost all chemical bonds include equal sharing of electrons among all atoms, regardless their relative electronegativity.

The structure for 1-nitrobutane, making sure to add all non-zero formal charges

There are four kind of molecule present in 1-nitrobutane and they are carbon, hydrogen , nitrogen and oxygen. Nitrogen is bonded with two oxygen atom out of them one oxygen atom is attached with single bond and second oxygen atom is bonded with double bond. Nitrogen has positive charge whereas oxygen has negative charge.

It is a kind of alkane in with nitro group is attached with alkane group.

To know more about 1-nitrobutane

brainly.com/question/25045923

#SPJ4

7 0

1 year ago

Is this an oxidation reaction? Why or why not?

murzikaleks [220]

The oxidation state of Hydrogen in reactant side is 0 and that in product side is +1. Hence the reaction is oxidation.

7 0

2 years ago