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Elena L [17]
3 years ago
13

A galvanic (voltaic) cell contains a copper cathode immersed in a copper(ii) chloride solution and a nickel anode immersed in a

nickel(ii) chloride solution. the two solutions are connected with a salt bridge. write the balanced equation for the galvanic cell. phases are optional.
Chemistry
1 answer:
aalyn [17]3 years ago
6 0
We can write the balanced equation for the galvanic cell by using the oxidation and reduction half-reactions. In the anode, Ni(s) is oxidized and produces aqueous Ni2+:
     Ni(s) → Ni2+
while in the cathode, Cu2+ is reduced and deposits copper:
      Cu2+ → Cu(s)
We now balance the charge of each reaction by adding electrons to the side of the equation with the greater charge:
     Ni(s) → Ni2+ + 2 e-
     Cu2+ + 2 e- → Cu(s)
Finally, we add the half-reactions to obtain the overall balanced equation for the galvanic cell:
     Cu2+(aq) + Ni(s) → Ni2+(aq) + Cu(s)
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Answer:

the compound contains C, H, and some other element of unknownidentity, so we can’t calculate the empirical formula

Explanation:

Mass of CO2 obtained = 3.14 g

Hence number of moles of CO2 = 3.14g/44.0 g = 0.0714 mol

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The mass of the carbon in the sample = 0.0717 mol × 1g/mol = 0.0717 g

% by mass of carbon = 0.857/1 ×100 = 85.7 %

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Mass of carbon and hydrogen = 85.7 + 7.17 = 92.87 %

Hence, there must be an unidentified element that accounts for (100 - 92.87) = 7.13% of the compound.

5 0
3 years ago
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Veronika [31]

Answer:

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Explanation:

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For SO₂,

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Now, for the ratio of both the above-calculated ratios,

\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}

The required ratio is 2:1

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hope this helps :)

if you need an explanation let me know!!

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