Answer:
TIMED HELP ASAP
19.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g・°C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.
Answer:
atoms and molecules
Explanation:
matter is made up of particles called atoms and molecules
Answer:
Pb(NO3)2 + K2CO3 ----> PbCO3 + 2KNO3
The answer is B. 2
Hope this helps!
Answer:
4 moles, 160 g
Explanation:
The formula for the calculation of moles is shown below:

For
:-
Mass of
= 196 g
Molar mass of
= 98 g/mol
The formula for the calculation of moles is shown below:

Thus,


According to the given reaction:

1 mole of sulfuric acid reacts with 2 moles of NaOH
So,
2 moles of sulfuric acid reacts with 2*2 moles of NaOH
Moles of NaOH must react = 4 moles
Molar mass of NaOH = 40 g/mol
<u>Mass = Moles*molar mass =
= 160 g</u>
If you would’ve attached a picture I’m sure it would’ve been a lot easier.