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zavuch27 [327]
3 years ago
13

* Gravity affects the mass of a brick. True False

Chemistry
2 answers:
Inessa05 [86]3 years ago
8 0

Answer:

True

Explanation:

Because anything that has mass also has gravity

Aleksandr [31]3 years ago
7 0
True because anything that has a mass is affected by gravity no matter what it is
You might be interested in
Please help I need the answer by today and it is very important! Which of the following statements best describes why the mass o
Juliette [100K]

D, because matter does not change in space but unlike gravity, which changes, matter, is the mass of it, which will stay the same unless there is a chemical change or, physical change, but not in this case, so the answer you are looking for is D. hope this enlarged your understanding and knowledge.

6 0
3 years ago
What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 (formula weight = 164 g/mol) in 115 g of
Citrus2011 [14]

Answer:

freezing point   (°C) of the solution =  - 3.34° C

Explanation:

From the given information:

The freezing point (°C) of a solution can be prepared by using the formula:

\Delta T = iK_fm

where;

i = vant Hoff factor

the vant Hoff factor is the totality of the number of ions in the solution

Since there are 1 calcium ion and 2 nitrate ions present in Ca(NO3)2, the vant Hoff factor = 3  

K_f = 1.86 °C/m

m = molality of the solution and it can be determined by using the formula

molality = \dfrac{mole \ of \ solute }{kg \ of \ solvent }

which can now be re-written as :

molality = \dfrac{mole \ of \ Ca(NO_3)_2}{kg \ of \  water}

molality = \dfrac{\dfrac{mass \ of \  \ Ca(NO_3)_2}{molar \  mass of \ Ca(NO_3)_2} }{kg \ of \  water}

molality = \dfrac{\dfrac{11.3 \ g }{164 \ g/mol} }{0.115 \ kg }

molality = 0.599 m

∴

The freezing point (°C) of a solution can be prepared by using the formula:

\Delta T = iK_fm

\Delta T =3 \times (1.86 \ ^0C/m) \times (0.599 \ m)

\Delta T =3.34^0 \ C

\Delta T = the freezing point of water - freezing point of the solution

3.34° C = 0° C -  freezing point of the solution

freezing point  (°C) of the solution =  0° C - 3.34° C

freezing point   (°C) of the solution =  - 3.34° C

3 0
3 years ago
How would you compare Uranus (a Jovian planet) to Earth (a terrestrial planet)?
kipiarov [429]
Answer:
Uranus is much bigger than Earth.
Explanation:
it’s about four times bigger than the watch, Uranus is about 31,000 miles in diameter while the earth is only about 7,900 miles.
3 0
3 years ago
A 3.5 M KNO3 solution contains 3.5 miles of KNO3 dissolved in A) 1.0 liter of solution B) 1.0 liter of solvent C) 3.5 liters of
Vladimir [108]
N=3.5 mol
c=3.5 mol/L

n=cv

v=n/c

v=3.5/3.5=1.0 L

A) 1.0 liter of solution
4 0
3 years ago
The amount of matter in a given space or volume
ivolga24 [154]

Answer:

i'm not sure but i think

Explanation:

matter Anything that has mass and occupies space.

density The amount of matter in a given volume of space.

formula for density mass divided by volume

physical property A property of matter that can be observed and measured, without changing its identity.

I hope it helps

5 0
3 years ago
Read 2 more answers
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