Divide and answer in simplest form :) 5/3÷3

When this exponent is applied to a nonzero base, the result is always 1

aleksandrvk [35]

Question :Why is it that any number raised to the power zero is equal to 1 and not zero ?

Answer :When a number is raise to the power 0, we are not actually multiplying the particular number by 0. For example, let us take 20. In this case we are not actually multiplying the number 2 by 0.

We define 20 = 1, so that each power of 2 is one factor of 2 larger than the last, e.g., 1,2,4,8,16,32...This involves the rules of exponents particularly division.

If a is a number and x and y are also numbers, then according to the rule of division for powers with the same base,

a^x/a^y = a^(x - y).

It says the quotient of two powers with the same base is equal to the common base raise to the exponent equal to the difference between x and y.

So, if x = y, then a^x/a^y = a^(x -y) = a^0

But a^x is equal to a^y, since x = y; hence a^x/a^y = 1

Therefore, by Transitive property of Equality,

a^0 = 1

Thus, this result says that number raised to the power zero is equal to 1.

4 0

3 years ago

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Find two positive numbers satisfying the given requirements. The product is 432 and the sum of the first plus three times the se

kogti [31]

Answer:

Step-by-step explanation:

Let the two positive integers be x and y.

If their product is 432, then

xy = 432 ......... 1

Also if the sum of the first plus three times the second is a minimum, then;

p(x) = x + 3y

From 1;

y = 432/x ..... 3

Substitute 3 into 2;

p(x) = x+3y

p(x)= x + 3(432/x)

p(x) = x + 1296/x

Since the expression is at minimum when dp(x)/dx = 0

dp/dx = 1 + (-1296)/x²

dp/dx = 1 -1296/x²

0 = 1 -1296/x²

0 = (x²-1296)/x²

cross multiply

0 = x²-1296

x² = 1296

x = √1296

x = 36

Since xy = 432

36y = 432

y = 432/36

y = 12

Hence the two positive numbers are 36 and 12

4 0

3 years ago

5-4. Solve each of the following equations for the indicated variable. Use your Equation Mat if it is helpful. Write down each o

balu736 [363]

QUESTION 1

The given equation is :

$2(y - 3) = 4$
We want to solve for y. This means we have to isolate y on one side of the equation while all other constants are also on the other side of the equation,

We first divide both sides by 2 to obtain,

$\frac{2(y - 3)}{2} = \frac{4}{2}$

We cancel out the common factors to get,

$y - 3 = 2$

We now group like terms to get,

$y = 3 + 2$

We simplify to obtain,

$y = 5$

QUESTION 2

The given equation is

$2x + 5y = 10$
We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

This implies that,

$2x= 10 - 5y$

We now divide through by 2, to obtain,

$\frac{2x}{2} = \frac{10}{2} - \frac{5y}{2}$

This will now give us,

$x = 5 - \frac{5}{2} y$

QUESTION 3

The given equation is
$6x + 3y = 4y + 11$

We want to solve for y. This means that we need to isolate y on one side of the equation, while all other variables and constants are also on the other side of the equation.

We first of all group all the y terms on one side of the equation to obtain,

$6x - 11 = 4y - 3y$

We simplify to get,

$6x - 11 = y$

This implies that,

$y = 6x - 11$

QUESTION 4

The given equation is,

$3(2x + 4) = 2 + 6x + 10$

We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

Let us first expand the brackets to get,

$6x + 12 = 2 + 6x + 10$
This implies that

$6x + 12 = 6x + 12$

We group like terms to get,

$6x - 6x = 12 - 12$

We now simplify both sides to get,

$0x = 0$

We don't want x to vanish, so let us try to divide both sides by zero to get,

$x = \frac{0}{0}$

This is an indeterminate form, which implies that, x has infinitely many solutions. This means that all the real numbers are solution to the equation.

$\therefore \: x \in \: R$

QUESTION 5

The given equation is,

$y = - 3x + 6$

We want to solve for x, so we add the additive inverse of 6, which is -6 to both sides of the equation to get,

$y - 6 = - 3x$

We rewrite this to obtain,

$- 3x = y - 6$

We divide through by -3 to get,

$\frac{ - 3x}{ - 3} = \frac{y}{ - 3} - \frac{6}{ - 3}$

This will give us,

$x = - \frac{y}{3} + 2$

or

$x= 2 - \frac{1}{3} y$

5 0

3 years ago

4x4 + 32x - 28 = 0 whats the answer to this

Stells [14]

Answer:

0

Step-by-step explanation:

4x4 + 32x - 28 = 0

5 0

3 years ago

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Which is better 9.95 for 30oz of coffee or 3.50 for 12oz of coffee

MaRussiya [10]

Answer:

9.95 for 30oz

Step-by-step explanation:

30/9.95 = 3.02

12/3.5 = 3.43

7 0

3 years ago

Divide and answer in simplest form :) 5/3÷3​

Divide and answer in simplest form :) 5/3÷3