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madreJ [45]
3 years ago
7

Divide and answer in simplest form :) 5/3÷3​

Mathematics
1 answer:
kifflom [539]3 years ago
6 0

Answer:

5/9

Step-by-step explanation:

5/3÷3

Copy dot flip

5/3 * 1/3

5/9

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Find the surface area of the two following figures. Show all your work.
Misha Larkins [42]

Answer:

First shape: 366 in^2

Second shape: 376 in^2

Pretty sure these are correct, hope this helps!

7 0
2 years ago
3a+4b=5a-t solve for a
7nadin3 [17]

Answer:

2b+t/2=a

Step-by-step explanation:

3a + 4b = 5a-t

-3a           -3a

4b = 2a - t

+t         +t

4b + t = 2a

/2           /2

2b+t/2=a

5 0
3 years ago
Read 2 more answers
What is the value of x in the equation 2x + 1/2x + 2(1+x) = 29?
erica [24]

Answer:

<h2>x = 6</h2>

Step-by-step explanation:

2x  +  \frac{1}{2} x + 2(1 + x) = 29

Multiply through by 2

That's

4x + x + 4(1 + x) = 58

<u>Expand</u>

That's

5x + 4 + 4x = 58

9x = 58 - 4

9x = 54

Divide both sides by 9

That's

\frac{9x}{9}  =  \frac{54}{9}

We have the final answer as

<h3>x = 6</h3>

Hope this helps you

5 0
2 years ago
This graph represents a transformation of the parent cube root function. Replace the values of h and k to create the equation of
Zigmanuir [339]

Answer: H is 5 and K is 2

Step-by-step explanation:

8 0
3 years ago
Which of the following would be an acceptable first step in simplifying the expression sinx/1-sinx
Paha777 [63]
\bf \textit{difference of squares}&#10;\\\\&#10;(a-b)(a+b) = a^2-b^2\qquad \qquad &#10;a^2-b^2 = (a-b)(a+b)&#10;\\\\\\&#10;\textit{also recall that }sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\&#10;-------------------------------

\bf \cfrac{sin(x)}{1-sin(x)}\implies \cfrac{sin(x)}{1-sin(x)}\cdot \cfrac{1+sin(x)}{1+sin(x)}\implies \stackrel{first~step}{\cfrac{sin(x)[1+sin(x)]}{[1-sin(x)][1+sin(x)]}}&#10;\\\\\\&#10;\cfrac{sin(x)[1+sin(x)]}{1^2-sin^2(x)}\implies \cfrac{sin(x)[1+sin(x)]}{cos^2(x)}&#10;\\\\\\&#10;\cfrac{sin(x)+sin^2(x)}{cos^2(x)}\implies \cfrac{sin(x)}{cos^2(x)}+ \cfrac{sin^2(x)}{cos^2(x)}&#10;\\\\\\&#10;\cfrac{sin(x)}{cos(x)}\cdot \cfrac{1}{cos(x)}+\cfrac{sin^2(x)}{cos^2(x)}\implies tan(x)sec(x)+tan^2(x)&#10;\\\\\\&#10;tan(x)[sec(x)+tan(x)]
8 0
3 years ago
Read 2 more answers
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