The correct answer is a Photon.
One photon is released for each event. Photons are elementary particles of all electromagnetic radiation, including light.
When the reaction equation is:
HF ↔ H+ + F-
and when the Ka expression
= concentration of products/concentration of reactions
so, Ka = [H+][F-]/[HF]
when we assume:
[H+] = [F-] = X
and [HF] = 0.35 - X
So, by substitution:
6.8 x 10^-4 = X^2 / (0.35 - X) by solving for X
∴ X = 0.015 M
∴[H+] = X = 0.015
when PH = -㏒[H+]
∴PH = -㏒0.015
= 1.8
Answer:
Density by giving the object it's weight/volume. State of matter by giving its chemical substances and physical shape.
Explanation:
State of matter, (solid, liquid, or a gas) determines the main physical property of a substance. If it's a liquid, it would have an indefinite shape/physical appearance. If the object is a solid than the shape would have a definite shape/physical appearance. Density is defined as mass per volume which means the weight of an object divided by the volume determines the density of the object. You would have the volume (the amount of space an object takes up) and the mass (weight of the object) if you have the objects density.
To conclude, both density and the objects state of matter determine the physical properties of a substance. "Density the weight and volume, and the state of matter is the shape/chemical properties of the substance."
Hope this helps.
Answer:
Explanation:
According to the Law of Conservation of Mass, the mass of the products must equal the mass of the reactants.
- mass products = mass reactants
In this problem, the reaction is:
- The reactants are iron and oxygen. We know the mass of the iron sample is 10 grams.
- The product is ferric oxide. The mass of the ferric oxide sample is 18.2 grams.
We want to find how many grams of oxygen reacted. We have to get the oxygen by itself. 10 is being added to oxygen. The inverse of addition is subtraction. Subtract 10 from both sides of the equation.
<u>8.2 grams of oxygen </u>reacted with 10 grams of iron to form 18.2 grams of ferric oxide.
